datetime-parsing

This question already has an answer here: How do I parse an ISO 8601-formatted date? 25 answers I have a datasets where all the dates have the following format: 2012-10-09T19:00:55Z I'd like to be able to be able to use methods like .weekday on them. How do I convert them to the proper format in Python? You can use dateutil.parser.parse to parse strings into datetime objects. dateutil.parser.parse will attempt to guess the format of your string, if you know the exact format in advance then you can use datetime.strptime which you supply a format string to (see Brent Washburne's answer). from

I want to convert below date into AEST format using Java. 2018-01-08T02:10:24.000+0000w Below is the code which i am using for to convert . DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSSzzz"); ZonedDateTime zdt = ZonedDateTime.parse( map.get("records-LastModifiedDate").toSt‌​ring().trim()); System.out.println(zdt); There is something wrong with the pattern? Please suggest. You have to use the formatter when parsing the date string. Also you need to tell it to change the zone or zone offset to get it into AEST/AEDT. This might work: DateTimeFormatter dtf =

I'd like a way to show natural times for dated items in Python. Similar to how Twitter will show a message from "a moment ago", "a few minutes ago", "two hours ago", "three days ago", etc. Django 1.0 has a "humanize" method in django.contrib. I'm not using the Django framework, and even if I were, it's more limited than what I'd like. Please let me (and generations of future searchers) know if there is a good working solution already. Since this is a common enough task, I imagine there must be something. While not useful to you at this very moment, it may be so for future searchers: The babel

Consider a historic date string of format: Thu Jan 9 12:35:34 2014 I want to parse such a string into some kind of C++ date representation, then calculate the amount of time that has passed since then. From the resulting duration I need access to the numbers of seconds, minutes, hours and days. Can this be done with the new C++11 std::chrono namespace? If not, how should I go about this today? I'm using g++-4.8.1 though presumably an answer should just target the C++11 spec. Simple std::tm tm = {}; std::stringstream ss("Jan 9 2014 12:35:34"); ss >> std::get_time(&tm, "%b %d %Y %H:%M:%S"); auto

I have a date time string that I don't know how to parse it in Python. The string is like this: Tue May 08 15:14:45 +0800 2012 I tried datetime.strptime("Tue May 08 15:14:45 +0800 2012","%a %b %d %H:%M:%S %z %Y") but Python raises 'z' is a bad directive in format '%a %b %d %H:%M:%S %z %Y' According to Python doc: %z UTC offset in the form +HHMM or -HHMM (empty string if the the object is naive). What is the right format to parse this time string? datetime.datetime.strptime has problems with timezone parsing. Have a look at the dateutil package : >>> from dateutil import parser >>> parser.parse