datetime-format

问题 The below answer to another thread seems to make a start on what I think I need, but I am having difficulties in implementing it. The best library for that purpose would probably be Globalize. It allows you to specify the locale (it is called culture but it is actually the same), the format (built-in or your own) and actually parse string to given date: var dateString = "lunes, 29 de agosto de 2011"; // seems like long date format in Spanish var date = Globalize.parseDate( dateString, "D",

问题 I'm writing an application to manipulate text data, Which will change the content of input string and create new output String based on the format of input string. I encounter some problem with recognized the date time string. Based on the document the input date time may have some optional section, here the sample pattern: yyyy[MM[dd[HHmm]]][Z] So after some digging on the web, my first attempt to use the parseBest function. public boolean checkFormatDate(string input){ DateTimeFormatter

问题 I have a Spring application and i receive a date from an angular client as a String, how can i convert this date to a Java Date, following is the TypeScript Date format : TypeScript Date Format : Mon Jan 04 2021 00:00:00 GMT+0100 (Central European Standard Time) Java Date Format : Mon Jan 04 00:00:00 CET 2021 回答1: java.time how can i convert this date to a Java Date, following is the TypeScript Date format : TypeScript Date Format : Mon Jan 04 2021 00:00:00 GMT+0100 (Central European Standard

问题 I have a data-frame and I want to send it in my Django template. dummy code in views.py : def graphs(request): df_new = pd.read_excel("/home/cms/cms/static/Sensorik.xlsx") times = df_new.loc[:, df_new.columns[0]].to_json(orient='records') # columns[0] contains datetime values data_color = df_georgian.loc[:, df_georgian.columns[2]] color = data_color.to_json(orient='records') context = { 'times': times, 'data_color': color, ... } return render(request, 'graphs/graphs.html', context) In my

问题 I have a data-frame and I want to send it in my Django template. dummy code in views.py : def graphs(request): df_new = pd.read_excel("/home/cms/cms/static/Sensorik.xlsx") times = df_new.loc[:, df_new.columns[0]].to_json(orient='records') # columns[0] contains datetime values data_color = df_georgian.loc[:, df_georgian.columns[2]] color = data_color.to_json(orient='records') context = { 'times': times, 'data_color': color, ... } return render(request, 'graphs/graphs.html', context) In my

问题 This question already has an answer here : Why pattern of datetimeformat is needed to avoid this causing a DateTimeParseException? [duplicate] Java 8 DateTimeFormatter for month in all CAPS not working [duplicate] (1 answer) Closed 7 months ago . I'm being passed a date in ths format - "JAN01/2020" but I can't seem to find the DateTimeFormatter pattern for it. I tried these (as well as several others) but they're resulting in DateTimeParseException - DateTimeFormatter.ofPattern("MMMd/YYYY")

问题 This question already has an answer here : Why pattern of datetimeformat is needed to avoid this causing a DateTimeParseException? [duplicate] Java 8 DateTimeFormatter for month in all CAPS not working [duplicate] (1 answer) Closed 7 months ago . I'm being passed a date in ths format - "JAN01/2020" but I can't seem to find the DateTimeFormatter pattern for it. I tried these (as well as several others) but they're resulting in DateTimeParseException - DateTimeFormatter.ofPattern("MMMd/YYYY")

问题 I have this code: String date = "2019-04-22T00:00:00+02:00"; OffsetDateTime odt = OffsetDateTime .parse(date, DateTimeFormatter.ISO_OFFSET_DATE_TIME) .withOffsetSameInstant(ZoneOffset.of("+00:00")); System.out.println(odt); This print: 2019-04-21T22:00Z How can I print 2019-04-21T22:00+00:00 ? With offset instead of Z . 回答1: None of the static DateTimeFormatter s do this in the standard library. They either default to Z or GMT . To achieve +00:00 for no offset, you will have to build your own

问题 I have this code: String date = "2019-04-22T00:00:00+02:00"; OffsetDateTime odt = OffsetDateTime .parse(date, DateTimeFormatter.ISO_OFFSET_DATE_TIME) .withOffsetSameInstant(ZoneOffset.of("+00:00")); System.out.println(odt); This print: 2019-04-21T22:00Z How can I print 2019-04-21T22:00+00:00 ? With offset instead of Z . 回答1: None of the static DateTimeFormatter s do this in the standard library. They either default to Z or GMT . To achieve +00:00 for no offset, you will have to build your own

问题 I discovered this issue in connection with Elastic Search queries, but since the ES date format documentation links to the API documentation for the java.time.format.DateTimeFormatter class, the problem is not really ES specific. Short summary: We are having problems with dates beyond year 9999, more exactly, years with more than 4 digits. The documents stored in ES have a date field, which in the index descriptor is defined with format "date", which corresponds to "yyyy-MM-dd" using the