date-difference

问题 I have the following query : select CONVERT(varchar(12), DATEADD(MILLISECOND, DateDiff(MILLISECOND, '2014-08-04 10:37:28.713','2014-11-04 08:21:17.723'), 0), 114) When I execute this, I get the error : "The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart." When I change the query to the following it works fine : select CONVERT(varchar(12), DATEADD(SECOND, DateDiff(SECOND, '2014

问题 This question already has answers here : Calculating the difference between two Java date instances (45 answers) Closed 5 years ago . can anyone tell how to subtract string "after" from "today" to get days difference. import java.text.*; import java.util.*; public class Main { public static void main(String args[]){ SimpleDateFormat sdf=new SimpleDateFormat("yyyy/MM/dd"); Calendar cal=Calendar.getInstance(); String today=sdf.format(cal.getTime()); System.out.println(today); cal.add(Calendar

问题 I'm wondering if there is some new and awesome possibility to get the amount of days between two NSDates in Swift / the "new" Cocoa? E.g. like in Ruby I would do: (end_date - start_date).to_i 回答1: You have to consider the time difference as well. For example if you compare the dates 2015-01-01 10:00 and 2015-01-02 09:00 , days between those dates will return as 0 (zero) since the difference between those dates is less than 24 hours (it's 23 hours). If your purpose is to get the exact day

问题 I know there are lots of questions on SO about how to get, but I want and example using new Java 8 Date api. I also know JodaTime library, but I want a work way without external libraries. Function needs to complain with these restrictions: Prevent errors from date savetime Input are two Date's objects (without time, I know localdatetime, but I need to do with date instances) 回答1: If you want logical calendar days , use DAYS.between() method from java.time.temporal.ChronoUnit: LocalDate

问题 How can I calculate hours worked on a project using specific working hours that aren't the same each day? So Monday - Friday I work 7 am-7 pm, Saturday 9 am -1 pm and I take Sunday off (lucky me). If i start a project on the 1st March 10 am and finish on the 5th March at 9 am how can I calculate an answer of 27 hours ?? I have two cells date/time start and date/time finish. I have multiple rows to do this to and several time points but this essentially will work the same. I hope makes sense.

问题 My requirement is to compute the total months and then broken months separately between 2 dates (ie first date from table and second date is current date). If broken months total count is > 15 then account it as one month experience and if its les than 15 don't account that as 1 month experience. Assume I have a date on table as 25/11/2018 and current date is 06/01/2019; the full month in between is December, so 1 month experience; and broken months are November and January, so now I have to

问题 I want to calculate the difference between 2 dates in months and days, I don't want to consider a month is 30 days and get the time in milliseconds and convert them, and I don't want to use a library such as Joda, and I also found a solution that uses LocalDate, however I am using Java 7. I looked for answers to my question but could not find any, and I tried many approaches, I tried creating a calendar and passed the time in milliseconds the difference between my 2 dates, but if I tried for

问题 If I have a date time in milliseconds, how do I check if its within 2 years of today in JavaScript ? So far, I have the following: var yearInMs = ( 1000 * 60 * 60 * 24 * 7 * 52 ); var givenTime = 1519183763504; var diff = givenTime - ( new Date().getTime()); diff = diff / yearInMs; if( diff > 2 ) alert('more than 2 years'); Is this correct ? How do account for things like leap years ? 回答1: Just at 2 years to today and see if it's greater than the supplied date or time value, e.g. var d = new

问题 I have some data which (broadly speaking) consist of following fields: Person TaskID Start_time End_time Alpha 1 'Wed, 18 Oct 2017 10:10:03 GMT' 'Wed. 18 Oct 2017 10:10:36 GMT' Alpha 2 'Wed, 18 Oct 2017 10:11:16 GMT' 'Wed, 18 Oct 2017 10:11:28 GMT' Beta 1 'Wed, 18 Oct 2017 10:12:03 GMT' 'Wed, 18 Oct 2017 10:12:49 GMT' Alpha 3 'Wed, 18 Oct 2017 10:12:03 GMT' 'Wed, 18 Oct 2017 10:13:13 GMT' Gamma 1 'Fri, 27 Oct 2017 22:57:12 GMT' 'Sat, 28 Oct 2017 02:00:54 GMT' Beta 2 'Wed, 18 Oct 2017 10:13:40

问题 This question already has answers here : Closed 8 years ago . Possible Duplicates: Calculating difference in dates in Java How can I calculate a time span in Java and format the output? Say you were given two dates as strings and they are in this format 8/11/11 9:16:36 PM how would I go about converting them to java Date objects so that I can then calculate the difference between two dates? 回答1: As long as both times are in GMT/UTC, you can do date1.getTime() - date2.getTime() and then divide