cut

I am working with the cut function to prep data for a barplot histogram but keep running into a seeming inconsistency between my labels and breaks: Error in cut.default(sample(1:1e+05, 500, T), breaks = sq, labels = sprintf("$%.0f", : labels/breaks length conflict Here is an example. I pretend that it is income data, using a sequence of 0 to $100,000 in bins of $10,000. I use the same variable to generate both breaks and labels, with minor formating on the label side. I thought they might for some reason have different lengths when comparing to a character vector, but they appear to have the

i'm trying to build a shell script to monitor some log files. I'm using a command like this: tail -f /var/somelog | grep --line-buffered " some test and p l a c e h o l d e r" | cut -f 3,4,14 -d " " the log file is like: some test and p l a c e h o l d e r 3 some test and p l a c e h o l d e r 4 some test and p l a c e h o l d e r 5 some test and p l a c e h o l d e r 6 and so on.. My issue is that the output of the command does not display the last line some test and p l a c e h o l d e r 6 until line some test and p l a c e h o l d e r 7 is added to the log. I hope I made clear my issue. Can

Operating System: OSX Method: From the command line, so using sed, cut, gawk, although preferably no installing modules. Essentially I am trying to take the first column of a csv file and parse it to a new file. Example input file EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 Desire output EXAMPLEfoo EXAMPLEbar EXAMPLE1 EXAMPLE2 EXAMPLE3 EXAMPLE4 So I want the first column. Here is what I have tried so far: awk -F"," '{print $1}' in.csv > out.txt awk -F"," '{for (i=2;i<=NF;i++)}' in.csv > out.txt awk -F"," 'BEGIN { OFS="," }' '{print $1}' in.csv > out

I'm trying to output the amount of free disk space on the filesystem /example . If I run the command df -k /example I can get good information about available disk space in kb but only by being human and actually looking at it. I need to take this data and use it somewhere else in my shell script. I initially thought about using cut but then my script wont be portable to other disks as free disk space will vary and cut will not produce accurate results. How can I get output of just the free disk-space of example in kb? fedorqui To get the output of df to display the data in kb you just need to

I would like to have help or direction on a problem I have in awk. I have a tab-delimited file with more than 5 fields. I want to output the fields excluding the first 5 fields. Could you please tell how to write an awk script to accomplish this task? Best, jianfeng.mao Do Note the following kind comment: There are many fields in my files. Different lines have a different number of fields. The number of fields per line is not standard. I agree with matchew's suggestion to use cut : it's the right tool for this job. But if this is just going to become a part of a larger awk script, here's how

I got this error for my code Error in t.test.default(dat$Value, x[[i]][[2]]) : not enough 'y' observations I think the reason I got this error is because I'm doing a t.test for data that only has one value (so there wouldnt be a mean or an sd) vs data that has 20 values..is there a way I can get around this.. is there a way I can ignore the data that doesn't have enough y observations??? like an if loop might work...pls help So my code that does the t.test is t<- lapply(1:length(x), function(i) t.test(dat$Value,x[[i]][[2]])) where x is data in the form of cuts similar to cut: [3:8) Number

I'm creating a simple audio editing tool to trim and delete from an audio. I implemented the trim function and it is working fine. However I searched and tried to implement the delete function and here is my code: func deleteExportAsset(_ asset: AVAsset, fileName: String, completeAudioTime: CGFloat) -> URL { print("\(#function)") let documentsDirectory = FileManager.default.urls(for: .documentDirectory, in: .userDomainMask)[0] let trimmedSoundFileURL = documentsDirectory.appendingPathComponent(fileName) print("saving to \(trimmedSoundFileURL.absoluteString)") if FileManager.default.fileExists

I need to get the java version number, for example "1.5", from python (or bash). I would use: os.system('java -version 2>&1 | grep "java version" | cut -d "\\\"" -f 2') But that returns 1.5.0_30 It needs to be compatible if the number changes to "1.10" for example. I would like to use cut or grep or even sed. It should be in one line. Considering an output like this: $ java -version java version "1.8.0_25" Java(TM) SE Runtime Environment (build 1.8.0_25-b17) Java HotSpot(TM) 64-Bit Server VM (build 25.25-b02, mixed mode) You can get the version number with awk like this: $ java -version 2>&1 |