cut

how can I delete characters from a String until a certain character with bash? Example: "ananas1kiwi2apple1banana2tree" shall look like this: "apple1banana2tree" Thank you! If you want to remove the substring upto 2 , using bash parameter expansion: ${var#*2} # does non-greedy match from left, use ## for greediness #*2 matches and discards upto first 2 from variable var Example: $ var='ananas1kiwi2apple1banana2tree' $ echo "${var#*2}" apple1banana2tree Inian Using pure bash shell parameter expansion . $ string="ananas1kiwi2apple1banana2tree" $ newString="${string#*2}" $ printf "%s\n" "

Yo, Alright been noodling on this one for a while: How copy/cut styled text without bringing along any style baggage (background-color, color, etc)? Couple of routes of attacks that have been foiled: Style the text differently using ::select? Doesn't work, ::style isn't copied Style the selected text using jQuery's select binding This only works for inputs, not p, divs Intercept and remove style by binding an event to copy/paste using jQuery? Can't access the copied object to remove stuff, tried using e.preventDefault(); then returning the event object but that didn't work either Modify the

How to remove all n characters from a particular string using shell scripts, ssl01:49188,,, ssl01:49188, ssl01:49188,,,,, ssl01:49188,ssl999999:49188,,,,, ssl01:49188,abcf999:49188,,,,, The output will be in the following format ssl01:49188 ssl01:49188 ssl01:49188 ssl01:49188,ssl999999:49188 ssl01:49188,abcf999:49188 To answer the title of you question with specifies cutting last n character in a string , you can use the substring extraction feature in Bash. me@home$ A="123456" me@home$ echo ${A:0:-2} # remove last 2 chars 1234 However, based on your examples you appear to want to remove all

My file looks like this abc ||| xyz ||| foo bar hello world ||| spam ham jam ||| blah blah I want to extract a specific column, e.g. I could have done: sed 's/\s|||\s/\\t/g' file | cut -f1 But is there other way of doing that? Since | is a valid regex expression, it need to be escaped \\| or put in square brackets [|] You can do this: awk -F' \\|\\|\\| ' '{print $1}' file Some other variation that work as well awk -F' [|][|][|] ' '{print "$1"}' file awk -F' [|]{3} ' '{print "$1"}' file awk -F' \\|{3} ' '{print "$1"}' file awk -F' \\|+ ' '{print "$1"}' file awk -F' [|]+ ' '{print "$1"}' file \

maybe there are enough questions and/or solutions for this, but I just can't help myself with this one question: I've got the following command I'm using in a bash-script: var=$(cat "$filename" | grep "something" | cut -d'"' -f2) Now, because of some issues I have to translate all the code to python. I never used python before and I have absolutely no idea how I can do what the postet commands do. Any ideas how to solve that with python? Abhijit You need to have better understanding of the python language and its standard library to translate the expression cat "$filename" : Reads the file cat

I'm looking at the example menu of the command cut() ( example(cut) ), specifically this part: cut> aaa <- c(1,2,3,4,5,2,3,4,5,6,7) cut> cut(aaa, 3) [1] (0.994,3] (0.994,3] (3,5] (3,5] (3,5] (0.994,3] [7] (3,5] (3,5] (3,5] (5,7.01] (5,7.01] Levels: (0.994,3] (3,5] (5,7.01] cut> cut(aaa, 3, dig.lab = 4, ordered = TRUE) [1] (0.994,2.998] (0.994,2.998] (2.998,5.002] (2.998,5.002] [5] (2.998,5.002] (0.994,2.998] (2.998,5.002] (2.998,5.002] [9] (2.998,5.002] (5.002,7.006] (5.002,7.006] Levels: (0.994,2.998] < (2.998,5.002] < (5.002,7.006] cut> ## one way to extract the breakpoints cut> labs <-