cut

If I want to cut a list of text using a string as a delimiter, is that possible? For example I have a directory where a list of shell scripts call same perl script say abc.pl So when I do $grep abc.pl * in that directory, it gives me following results xyz.sh: abc.pl 1 2 xyz2.sh: abc.pl 2 mno.sh: abc.pl 3 pqr.sh: abc.pl 4 5 I basically want all the output after "abc.pl" (to check what range arguments are being passed to the perl right now) When I tried $grep abc.pl * | cut -d'abc.pl' -f2 OR $grep abc.pl * | cut -d'abc\.pl' -f2 its giving me cut: invalid delimiter When I read man for cut it

I have a config.txt file with IP addresses as content like this 10.10.10.1:80 10.10.10.13:8080 10.10.10.11:443 10.10.10.12:80 I want to ping every ip address in that file #!/bin/bash file=config.txt for line in `cat $file` do ##this line is not correct, should strip :port and store to ip var ip=$line|cut -d\: -f1 ping $ip done I'm a beginner, sorry for such a question but I couldn't find it out myself. The awk solution is what I would use, but if you want to understand your problems with bash, here is a revised version of your script. #!/bin/bash -vx ##config file with ip addresses like 10.10

I need to cut letter X out of a word: For example: I need to cut the first letter out of Star Wars, the fourth out of munich,... 1 star wars 4 munich 5 casino royale 7 the fast and the furious 52 a fish called wanda to tar wars munch casio royale the fat and the furious a fish called wanda I already tried it with cut, but it didn't work. This was my command: sed 's/^\([0-9]*\) \(.*\)/ echo \2 | cut -c \1/' So it gave me this output: echo star wars | cut -c 5 echo munich | cut -c 5 echo casino royale | cut -c 5 echo the fast and the furious | cut -c 5 echo a fish called wanda | cut -c 52 And

I am trying to find a way to to extract text from a variable with words separated by a forward slash. I attempted it using cut , so here's an example: set variable = '/one/two/three/four' Say I just want to extract three from this, I used: cut -d/ -f3 <<<"${variable}" But this seems to not work. Any ideas of what I'm doing wrong? Or is there a way of using AWK to do this? You need to remove the spaces before and after to = during string or variable assignment. And tell the cut command to print the 4th field. $ variable='/one/two/three/four' $ cut -d/ -f4 <<<"${variable}" three With the

Ca data <- cut(data$Time, breaks=seq(0, max(data$Time)+400, 400))  by(data$Oxytocin, cuts, mean) but this would only work for only one person's data....But I have ten people with their own Time and oxytocin data....How would I get their averages simultaneously? Also instead of having this type output : cuts: (0,400] [1] 0.7 ------------------------------------------------------------ cuts: (400,800] [1] 0.805 Is there a way I can get a list of those cuts? Here's a solution using IRanges package. idx assumes your data format is Time , data , Time , data , ... and so on.. So, it creates indices

I have a text file with bunch of commands, for example: ls -l /bin/bash/ cat file.txt bash cat somethingElse What I have to do is, get the names of commands ( ls , cat , bash ) and count them. I already did this: cut -d' ' -f1 file.txt | tr ' ' '\n' | sort | uniq -c This works almost as I would like to--output is: 1 bash 1 /bin/bash 2 cat 1 ls The only thing is wrong here, it has to IGNORE ABSOLUTE paths, so the output must look like this 2 bash 2 cat 1 cat I was trying with a while loop with a if statement in it which checks if there is a "/" in a line, but it doesn't seem to work. With awk