cut

I have a .CSV file (file.csv) whose data are all enclosed in double quotes. Sample format of the file is as below: column1,column2,column3,column4,column5,column6, column7, Column8, Column9, Column10 "12","B000QRIGJ4","4432","string with quotes, and with a comma, and colon: in between","4432","author1, name","890","88","11-OCT-11","12" "4432","B000QRIGJ4","890","another, string with quotes, and with more than, two commas: in between","455","author2, name","12","455","12-OCT-11","55" "11","B000QRIGJ4","77","string with, commas and (paranthesis) and : colans, in between","12","author3, name",

How can I delete a column from a CSV file which has comma separated value with a string enclosed in double quotes and a comma in between? I have a file 44.csv with 4 lines including the header like the below format: column1, column2, column3, column 4, column5, column6 12,455,"string with quotes, and with a comma in between",4432,6787,890,88 4432,6787,"another, string with quotes, and with two comma in between",890,88,12,455 11,22,"simple string",77,777,333,22 I need to cut the 1,2,3 columns from the file, so I used the cut command as below cut -d"," -f1,2,3 44.csv > 444.csv I am getting the

Can cut be used in bash with the ¬ delimiter? This question is an extension of the topic covered here . One interpretation of the goal in that link is to use a delimiter that can not be found (or very rarely found) in human text. Say we choose the 'Not Sign' ( ¬ ) as a delimiter. My question is regarding the use of cut to pull specific columns of a file with said delimiter. For example, say that we create a file with the ¬ delimiter. The file prac.txt might look like: $cat prac.txt "Billy""Car"¬"Red"¬"Garage"¬"3" "Rob"¬"Truck"¬"Blue"¬"Street"¬"14" The following process produces an error: $cut

I have a list with population, year, and county and I need to cut the list, and then find the number of uniq counties. The list starts off like this: #Population, Year, County 3900, 1969, Beaver 3798, 1970, Beaver 3830, 1971, Beaver 3864, 1972, Beaver 3993, 1973, Beaver 3976, 1974, Beaver 4064, 1975, Beaver There is much more to this list, and many more counties. I have to cut out the county column, sort it, and then output the number of uniq counties. I tried this command: cut -c3- list.txt | sort -k3 | uniq -c But this does not cut the third list, nor does it sort it alphabetically. What am

To simplify the discussion, let N = 3 . My current approach to extracting the last three characters of every line in a file or stream is to use sed to capture the last three characters in a group and replace the entire line with that group. sed 's/^.*\(.\{3\}\)/\1/' It works but it seems excessively verbose, especially when we compare to a method for getting the first three characters in a line. cut -c -3 Is there a cleaner way to extract the last N characters in every line? It's very simple with grep -o '...$' : cat /etc/passwd | grep -o '...$' ash /sh /sh /sh ync /sh /sh /sh Or better yer: N

I'm trying to figure out how to cut part of a string in C. For example you have this character string "The dog died because a car hit him while it was crossing the road" how would a function go making the sentence "a car hit him while crossing the road" or "a car hit him" How do you go about this with C's library (or/and) a custom function? ok I don't have the main code but this is going to be the structure of this experiment #include <ctype.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <string.h> #include <getopt.h> #include "display_usage.c"/*If the user enters wrong