crontab

问题 I did the following to implement cron jobs in rails 3 using a "runner" instead of a rake task. Step 1: I have whenever gem installed and scheduler.rb has following: set :environment, 'development' set :output, { :error => "/log/error.log", :standard => "/log/cron.log" } every 1.minute do runner "Cron.sendAutomaticsSMS()" end Step 2: Cron file: lib/cron.rb class Cron < ActiveRecord::Base def **sendAutomaticsSMS**() ----some code here --- end end Step 3: whenever --update-crontab --set

问题 I did the following to implement cron jobs in rails 3 using a "runner" instead of a rake task. Step 1: I have whenever gem installed and scheduler.rb has following: set :environment, 'development' set :output, { :error => "/log/error.log", :standard => "/log/cron.log" } every 1.minute do runner "Cron.sendAutomaticsSMS()" end Step 2: Cron file: lib/cron.rb class Cron < ActiveRecord::Base def **sendAutomaticsSMS**() ----some code here --- end end Step 3: whenever --update-crontab --set

问题 I am trying to run a .class file from a bash script every 1 minute using the crontab. I get the error Could not find or load main class Cron_Read_Send_CapacityData_To_Graphite. I have already set environment variable on my machine. If i run the bash script from the terminal it works fine.Note the bash script and the java class file are in the same folder Script: $ cat Run_Cron_Read_Send_CapacityData_To_Graphite.sh #!/bin/bash java Cron_Read_Send_CapacityData_To_Graphite >> /home/marshell

问题 Hi I am really new in Linux:D I made a crontab program which is supposed to print current time in console every 3 minutes. What I did is below. I made a crontab. In terminal, command " crontab -e " and add a phrase " */3 * * * * /home/user/a.out " a.out is a result file of " gcc WowCron.c ". Code is below. int main (int argc, char* argv[]){ time_t now; time(&now); printf("this is what we call cron does: %s\n", ctime(&now)); return 0; } and it works wonderfully when run individually. Then I

问题 I have a crontab file at /etc/crontab. I didn't place it there, it was already there, along with a lot of other files in /etc. However, when I type the command crontab -e, it creates a new file. I want it to look for crontab in /etc. This is what the command line says when I type crontab -e. no crontab for root - using an empty one ~ ~ ~ ~ ~ "/tmp/crontab.vx7AxR" 0L, 0C After a complete edit, this is what I end up with. Any ideas? [root@server ~]# crontab -e no crontab for root - using an

问题 I use crontab to run some programs automatically everyday. since 7 days ago whenever I run one of program automatically(every day at 3 am) to insert some strings(contains numbers and English and non-English letters) to a table in database, only numbers and english characters(ASCII chars) insert to database but before that time it was working fine. but when I run the program by myself,the other characters will insert to table,too. on the other hand, I run another program with crontab at 2 am

问题 I have a PHP script that is being called every minute by crontab like this: * * * * * /usr/bin/php /var/www/html/cronjobs/watchdog/watchdogExec.php The script executes a number of other PHP scripts and passes a variable like so: $ccmd = "nohup sudo /usr/bin/php watchdog.php " . $var . " &"; exec($ccmd); When called from a browser, watchdogExec.php runs fine and does its job. However when I added the cronjob, the script is not working and is spamming mails with the following error: No entry

问题 Is it possible to output stdout to file, but ignore stderr ? I have a Python script that uses sys.stderr.write(error) to output errors to stderr . I'd like to ignore these for this particular script. How is this possible? Here is the current entry in the crontab: * * * * * /Users/me/bin/scrape-headlines /Users/me/proxies.txt >> /Users/me/headlines.txt 2>&1 scrape-headlines is a bash script that calls the Python script. 回答1: The 2>&1 redirects stderr to stdout , appending it to the headlines

问题 I've got about a dozen servers that each have crontabs with anywhere from 20-50 crontab entries. My single most common cause of a process failure is someone commenting out jobs in cron during a fix or patch and then forgetting to uncomment the jobs. I'd like to do two things to solve this: Start using our schedule suppression process that allows users to suppress schedules without actually touching crontab. Nothing magical - just touch a file in a directory dedicated to the process. The

问题 I want to schedule a command every 1 hour and 1 minute. For example, if the first command executes at 01:01 pm, the next command will execute at 01:02PM; the time between the command executions is 1 hour and 1 minute. I tried using */1 */1 * * * but it runs every minute. Can anyone help me? 回答1: There's no way in crontab to schedule a job to run every 61 minutes (which, BTW, is an odd thing to want to do), but you can do it indirectly. You can schedule a job to run every minute: * * * * *