counter

How to count website contact form submissions without database [closed]

*爱你&永不变心* 提交于 2020-01-07 08:54:07
问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 6 years ago . Hi I'm new here and have a question about SMTP mail PHP function. I created a contact form which sends an HTML email to the company.

mapreduce中counter的使用

痴心易碎 提交于 2020-01-07 07:51:21
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> MapReduce Counter为提供我们一个窗口:观察MapReduce job运行期的各种细节数据。 MapReduce自带了许多默认Counter。 Counter有"组group"的概念,用于表示逻辑上相同范围的所有数值。MapReduce job提供的默认Counter分为三个组 Map-Reduce Frameword Map input records,Map skipped records,Map input bytes,Map output records,Map output bytes,Combine input records,Combine output records,Reduce input records,Reduce input groups,Reduce output records,Reduce skipped groups,Reduce skipped records,Spilled records File Systems FileSystem bytes read,FileSystem bytes written Job Counters Launched map tasks,Launched reduce tasks,Failed map tasks,Failed

How to create file download counter?

好久不见. 提交于 2020-01-06 08:51:55
问题 Which is the most simple way to create code ( with PHP and SQL ) which will count the file downloads ? I already have an integer column in the base dedicated for this feature... ( link to some example will also be welcomed ) 回答1: Create an sql table with two columns: Full path to file (primary key) Counter Setup your links for downloading to go to a php script. In that script, lookup the appropriate table row based on the full path, increment it's count, then redirect the browser to the file

How to create file download counter?

雨燕双飞 提交于 2020-01-06 08:51:23
问题 Which is the most simple way to create code ( with PHP and SQL ) which will count the file downloads ? I already have an integer column in the base dedicated for this feature... ( link to some example will also be welcomed ) 回答1: Create an sql table with two columns: Full path to file (primary key) Counter Setup your links for downloading to go to a php script. In that script, lookup the appropriate table row based on the full path, increment it's count, then redirect the browser to the file

Fast/Efficient counting of list of space delimited strings in Python

自古美人都是妖i 提交于 2020-01-06 03:06:41
问题 Given the input: x = ['foo bar', 'bar blah', 'black sheep'] I could do this to get the count of each word in the list of space delimited string: from itertools import chain from collections import Counter c = Counter(chain(*map(str.split, x))) Or I could simple iterate through and get: c = Counter() for sent in x: for word in sent.split(): c[word]+=1 [out]: Counter({'bar': 2, 'sheep': 1, 'blah': 1, 'foo': 1, 'black': 1}) The question is which is more efficient if the input list of string is

Fast/Efficient counting of list of space delimited strings in Python

痴心易碎 提交于 2020-01-06 03:06:10
问题 Given the input: x = ['foo bar', 'bar blah', 'black sheep'] I could do this to get the count of each word in the list of space delimited string: from itertools import chain from collections import Counter c = Counter(chain(*map(str.split, x))) Or I could simple iterate through and get: c = Counter() for sent in x: for word in sent.split(): c[word]+=1 [out]: Counter({'bar': 2, 'sheep': 1, 'blah': 1, 'foo': 1, 'black': 1}) The question is which is more efficient if the input list of string is

How to create some kind of iterator (or artificial id) for a given set of rows?

房东的猫 提交于 2020-01-05 16:53:15
问题 Sorry for the dumb title, but I simply don't know how to call it. Here's what I want. Look at the following query: SELECT * FROM ( SELECT xyz ) JOIN ... ORDER BY RANDOM() I want to know the initial order of the xyz rows when the query is over. So I thought about something like this (pseudo SQL): iterator = 1; SELECT * FROM ( SELECT iterator++, xyz ) JOIN ... ORDER BY RANDOM() So afterwards my result set will look like this: iterator | some other data -------------------------- 5 | ... 1 | ...

How to create some kind of iterator (or artificial id) for a given set of rows?

馋奶兔 提交于 2020-01-05 16:48:51
问题 Sorry for the dumb title, but I simply don't know how to call it. Here's what I want. Look at the following query: SELECT * FROM ( SELECT xyz ) JOIN ... ORDER BY RANDOM() I want to know the initial order of the xyz rows when the query is over. So I thought about something like this (pseudo SQL): iterator = 1; SELECT * FROM ( SELECT iterator++, xyz ) JOIN ... ORDER BY RANDOM() So afterwards my result set will look like this: iterator | some other data -------------------------- 5 | ... 1 | ...

CSS, UL/OL: Incorrect indent with custom counter

淺唱寂寞╮ 提交于 2020-01-05 08:48:37
问题 Update: this problem has found a very satisfactory solution, but in production side effects popped up which I describe in this thread. So, I'm using a custom counter in my OLs to get numbering like "1 - 1.1 - 1.1.1" Works fine. But when I do this, the indentation of the LI is wrong. The text aligns with the left edge of the number, not with the right edge (like standard OLs do). Edit: To get the numbers layouted the way I want, I had to mess with the standard paddings/margins of the OL. Now

Java ArrayList Item Counter ie “Apple, 3×Banana, 2×Orange”

百般思念 提交于 2020-01-05 08:22:56
问题 I'm sure this isn't a hugely complex problem but I'm relatively new to java and have been puzzling with this one for a while. Say I have an array which contains 6 string values, and lets say they are: [Apple, Banana, Banana, Banana, Orange, Orange] . I am looking to build a method that will take this array and return a string, in the case above, as: "Apple, 3×Banana, 2×Orange" . I would greatly appreciate some help with this. I've been trying different techniques to achieve this but fall down