conduit

网络安全技术-10章(计算机网络技术应用考试考点3级)

╄→尐↘猪︶ㄣ 提交于 2020-02-27 15:08:16
防火墙的访问模式有非特权模式、特权模式、配置模式和监视模式四种,其中监视模式下可以进行操作系统镜像更新、口令恢复等操作。 入侵防护系统主要分为三种: 基于主机的入侵防护系统、安装在受保护的主机系统中,检测并阻挡针对本机的威胁和攻击。 基于网络的入侵防护系统布置在网络的出口处,一般串联与防火墙与路由器之间,网络进出的数据流都必须经过他。 应用入侵防护系统 一般部署应用服务器前端,将基于主机和入侵防护系统功能延伸到服务器之前的高性能网络设备 上。 可信计算机系统评估将计算机系统的安全可靠 从低到高分为四类,7个级别 D级 最小保护 该级的计算机系统除了物理上的安全设施外,没有任何安全措施,任何人只要启动系统就可以访问系统 就可以访问系统的资源和数据。 C1级 自主保护类 具有自主访问控制机制,用户登录时 需要进行身份鉴别。 C2级 自主保护类 具有审计和验证机制 B1级 强制安全保护类 引入强制访问控制机制,能够对于主体和客体的安全进行管理。 B3级 具有硬件支持的安全域分离措施,从而保证安全域中软件和硬件的完整性、提供可以信通道。 A1级 要求对安全模型 备份的恢复速度从快到慢依次为完全备份、差异备份、增量备份。 SQL注入,通常把sql命令插入到web表单递交或输入域名或网页请求的查询字符串中,最终达到欺骗服务器执行恶意的SQL命令。

connecting http-conduit to xml-conduit

蓝咒 提交于 2020-01-13 11:02:41
问题 I'm struggling converting a Response from http-conduit to an XML document via xml-conduit. The doPost function takes an XML Document and posts it to the server. The server responds with an XML Document. doPost queryDoc = do runResourceT $ do manager <- liftIO $ newManager def req <- liftIO $ parseUrl hostname let req2 = req { method = H.methodPost , requestHeaders = [(CI.mk $ fromString "Content-Type", fromString "text/xml" :: Ascii) :: Header] , redirectCount = 0 , checkStatus = \_ _ ->

connecting http-conduit to xml-conduit

一世执手 提交于 2020-01-13 11:02:10
问题 I'm struggling converting a Response from http-conduit to an XML document via xml-conduit. The doPost function takes an XML Document and posts it to the server. The server responds with an XML Document. doPost queryDoc = do runResourceT $ do manager <- liftIO $ newManager def req <- liftIO $ parseUrl hostname let req2 = req { method = H.methodPost , requestHeaders = [(CI.mk $ fromString "Content-Type", fromString "text/xml" :: Ascii) :: Header] , redirectCount = 0 , checkStatus = \_ _ ->

Conduit: Multiple Stream Consumers

戏子无情 提交于 2020-01-12 17:25:30
问题 I write a program which counts the frequencies of NGrams in a corpus. I already have a function that consumes a stream of tokens and produces NGrams of one single order: ngram :: Monad m => Int -> Conduit t m [t] trigrams = ngram 3 countFreq :: (Ord t, Monad m) => Consumer [t] m (Map [t] Int) At the moment i just can connect one stream consumer to a stream source: tokens --- trigrams --- countFreq How do I connect multiple stream consumers to the same stream source? I would like to have

What are the pros and cons of Enumerators vs. Conduits vs. Pipes?

我的梦境 提交于 2020-01-09 12:18:08
问题 I'd like to hear from someone with a deeper understanding than myself what the fundamental differences are between Enumerators, Conduits, and Pipes as well as the key benefits and drawbacks. Some discussion's already ongoing but it'd be nice to have a high-level overview. 回答1: Enumerators/Iteratees as an abstraction were invented by Oleg Kiselyov. They provide a clean way of doing IO with predictable (low) resource requirements. The current Enumerators package is pretty close to Oleg's

What are the pros and cons of Enumerators vs. Conduits vs. Pipes?

夙愿已清 提交于 2020-01-09 12:17:50
问题 I'd like to hear from someone with a deeper understanding than myself what the fundamental differences are between Enumerators, Conduits, and Pipes as well as the key benefits and drawbacks. Some discussion's already ongoing but it'd be nice to have a high-level overview. 回答1: Enumerators/Iteratees as an abstraction were invented by Oleg Kiselyov. They provide a clean way of doing IO with predictable (low) resource requirements. The current Enumerators package is pretty close to Oleg's

How can I get a value after running a conduit?

一笑奈何 提交于 2020-01-06 02:21:10
问题 I need to do a little back and forth between with client and get either the Client object or their name string before starting up more pipelines. But I can't seem to get appSink to let me have a return value. How should I do this? checkAddClient :: Server -> ClientName -> AppData -> IO (Maybe Client) checkAddClient server@Server{..} name app = atomically $ do clientmap <- readTVar clients if Map.member name clientmap then return Nothing else do client <- newClient name app writeTVar clients $

Conduit - Multiple output file within the pipeline

▼魔方 西西 提交于 2020-01-01 09:09:11
问题 I'm writing a programme where an input file is split into multiple files (Shamir's Secret Sharing Scheme). Here's the pipeline I'm imagining: source: use Conduit.Binary.sourceFile to read from the input conduit: Takes a ByteString, produces [ByteString] sink: Takes [ByteString] from the conduit, and write each ByteString (in [ByteString]) to their corresponding file. (say if our input [ByteString] is called bsl, then bsl !! 0 will be written to file 0, bsl !! 1 to file 1 and so on) I found a

Conduit - Multiple output file within the pipeline

强颜欢笑 提交于 2020-01-01 09:09:07
问题 I'm writing a programme where an input file is split into multiple files (Shamir's Secret Sharing Scheme). Here's the pipeline I'm imagining: source: use Conduit.Binary.sourceFile to read from the input conduit: Takes a ByteString, produces [ByteString] sink: Takes [ByteString] from the conduit, and write each ByteString (in [ByteString]) to their corresponding file. (say if our input [ByteString] is called bsl, then bsl !! 0 will be written to file 0, bsl !! 1 to file 1 and so on) I found a

How to fix this Conduit code invovling the appearance of a list type where I do not expect one?

£可爱£侵袭症+ 提交于 2019-12-24 15:57:00
问题 I've been struggling with this Conduit code for a while, any help would be extremely appreciated. It is sort of like this code has been evolving by random mutation while the type checker is enforcing natural selection. Here is one of the fittest candidates I have so far: import Conduit import qualified Data.Conduit.Combinators as DCC import Data.CSV.Conduit import Data.Function ((&)) import Data.List.Split (splitOn) import Data.Map as DM import Data.Text (Text) import qualified Data.Text as