charat

Code: public void placeO(int xpos, int ypos) { for(int i=0; i<3;i++) for(int j = 0;j<3;j++) { // The line below does not work. what can I use to replace this? if(position[i][j]==' ') { position[i][j]='0'; } } } Change it to: if(position[i][j] == 0) Each char can be compared with an int. The default value is '\u0000' i.e. 0 for a char array element. And that's exactly what you meant by empty cell , I assume. To test this you can run this. class Test { public static void main(String[] args) { char[][] x = new char[3][3]; for (int i=0; i<3; i++){ for (int j=0; j<3; j++){ if (x[i][j] == 0){ System

In the 15th line ch = s1.charAt(0); , why ch is not getting the 0th word of s1, i.e., the operator . I've tried without using the try-catch method but then the error was regarding the exception and now no exception, no errors but the program don't ask for operator and directly after inputting the 1st and 2nd value , it shows the exception"can't do that" please post your kind replies, thanks import java.util.Scanner; class apples { public static void calcu() { try{ int a, b; String s1; char ch; Scanner sc = new Scanner(System.in); System.out.print("Enter the 1st value : "); a = sc.nextInt();

What is wrong with this function? I am lost thanks for help. function titleCase(str) { var splitStr = str.toLowerCase().split(' '); for (var i = 0; i < splitStr.length; i++) { if (splitStr.length[i] < splitStr.length) { splitStr[i].charAt(0).toUpperCase(); } str = splitStr.join(' '); } return str; } titleCase("I'm a little tea pot"); somethinghere You are not assigning your changes to the array again, so all your efforts are in vain. Try this: function titleCase(str) { var splitStr = str.toLowerCase().split(' '); for (var i = 0; i < splitStr.length; i++) { // You do not need to check if i is