How to check 2 charAt(i)

问题

I have this lines:

812.12 135.14 646.17 1
812.12 135.14 646.18 1
812.12 135.14 646.19 10
812.12 135.14 646.20 10
812.12 135.14 646.21 100
812.12 135.14 646.22 100

I want to delete only the last group so I did code like this:

if(lines[i].charAt(lines[i].length())-1>= '0'&&lines[i].charAt(lines[i].length()-1)<= '9'){
    lines[i] = lines[i].substring(0, lines[i].length()-1);
   }

   else if(lines[i].charAt(lines[i].length())>='10'+c&&lines[i].charAt(lines[i].length()-1)<='99'){
   lines[i] = lines[i].substring(0, lines[i].length()-2);
        }

   else if(lines[i].charAt(lines[i].length())>='100'&&lines[i].charAt(lines[i].length()-1)<='999){
   lines[i] = lines[i].substring(0, lines[i].length()-3);
 }

And it's now working for me I need help please

回答1:

It isn't working it says a wrong on this line:

lines[i] = lines[i].substring(0, index);

@Everyone

回答2:

You have characters and trying to compare them as numbers. It doesn't work that way.

A char in most higher-level (Java, .NET languages...etc) programming languages follows UTF-16 format by default. Since each char size is 2 bytes it can follow any encoding you need.

You cannot compare a char to string and you cannot attempt to put string in char like '10'. Those are two characters, not one, it's a string.

Now based on your desired output, you would like to remove everything after the last space. To do that, you can use the following code:

static void updateLines(String[] lines){
    for(int i=0;i<lines.length; i++){
        // get index of the last space
        int index = lines[i].lastIndexOf(" ");

        // remove everything after the last space
        lines[i] = lines[i].substring(0, index);
    }
}


public static void main(String[] args) {
    String[] lines = new String[]{
      "812.12 135.14 646.17 1",
      "812.12 135.14 646.18 1",
      "812.12 135.14 646.19 10",
      "812.12 135.14 646.20 10",
      "812.12 135.14 646.21 100", 
      "812.12 135.14 646.22 100",
      "812.12 135.14 646.23 1000",
      "812.12 135.14 646.24 1000"
    };

    updateLines(lines);

    for(int i=0;i<lines.length;i++)
        System.out.println(lines[i]);
}

Output:

812.12 135.14 646.17
812.12 135.14 646.18
812.12 135.14 646.19
812.12 135.14 646.20
812.12 135.14 646.21
812.12 135.14 646.22
812.12 135.14 646.23
812.12 135.14 646.24

Is this enough or do you need to compare numbers?

来源：https://stackoverflow.com/questions/47273979/how-to-check-2-charati

标签

char

charat