charat

问题 in a string like "phone" i want to know the neighbour of the character 'o' in this case 'h' and 'n' i tryed with a String Iterator but that gives me either before or after and with charAt() i will be out of range by -1 or endless loop String s = textArea.getText(); for( int i = 0; i < s.length(); i++) { char ch = s.charAt(i); char tz = s.charAt(i--); System.out.print(ch); if(ch == 'n') { System.out.print(tz); break; } } 回答1: you could try something like this. Of course, you can still do

问题 in a string like "phone" i want to know the neighbour of the character 'o' in this case 'h' and 'n' i tryed with a String Iterator but that gives me either before or after and with charAt() i will be out of range by -1 or endless loop String s = textArea.getText(); for( int i = 0; i < s.length(); i++) { char ch = s.charAt(i); char tz = s.charAt(i--); System.out.print(ch); if(ch == 'n') { System.out.print(tz); break; } } 回答1: you could try something like this. Of course, you can still do

问题 I need to create a program that will take a word without spaces, punctuation, and all lowercase, and rearranges the letters randomly. It needs to have substrings or charAt, I cannot use an array since we have not learned them yet. It also hsa to be different everytime, really n! times I think. This is what I have so far- public static void main(String[] args) { Scanner kboard = new Scanner(System.in); System.out.println("Enter a word that is less than 11 lowercase letters and has no

问题 I need to create a program that will take a word without spaces, punctuation, and all lowercase, and rearranges the letters randomly. It needs to have substrings or charAt, I cannot use an array since we have not learned them yet. It also hsa to be different everytime, really n! times I think. This is what I have so far- public static void main(String[] args) { Scanner kboard = new Scanner(System.in); System.out.println("Enter a word that is less than 11 lowercase letters and has no

问题 I am trying to figure out "what 5-digit number when multiplied by 4 gives you its reverse?" using this code but I get error: Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 5 at java.lang.String.charAt(String.java:658) at Digits.main(Digits.java:12) public class Digits{ public static void main(String[] args) { int n = 0; int b = 0; String number = Integer.toString(n); String backwards = Integer.toString(b); for (int x = 9999; x < 100000 ; x++ )

问题 I am trying to make a program that uses three digit numbers to identify items and I am trying to use something like the charAt method for integers or something. Im not too sure. Im a beginner and I apologize i just need help. Also I need a bit of help to use an if statement and relational operators. Im trying to do if the last digit in the number is less than 5 then it is {item} and if its greater than 5 then its this {item}. Something like that. Thank you so much in advance. String number;

问题 Code: public void placeO(int xpos, int ypos) { for(int i=0; i<3;i++) for(int j = 0;j<3;j++) { // The line below does not work. what can I use to replace this? if(position[i][j]==' ') { position[i][j]='0'; } } } 回答1: Change it to: if(position[i][j] == 0) Each char can be compared with an int. The default value is '\u0000' i.e. 0 for a char array element. And that's exactly what you meant by empty cell , I assume. To test this you can run this. class Test { public static void main(String[] args

问题 In the 15th line ch = s1.charAt(0); , why ch is not getting the 0th word of s1, i.e., the operator . I've tried without using the try-catch method but then the error was regarding the exception and now no exception, no errors but the program don't ask for operator and directly after inputting the 1st and 2nd value , it shows the exception"can't do that" please post your kind replies, thanks import java.util.Scanner; class apples { public static void calcu() { try{ int a, b; String s1; char ch

问题 Quick question. I have this code in a program: input = JOptionPane.showInputDialog("Enter any word below") int i = 0; for (int j = 0; j <= input.length(); j++) { System.out.print(input.charAt(i)); System.out.print(" "); //don't ask about this. i++; } Input being user input i being integer with value of 0, as seen Running the code produces this error: Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 6 at java.lang.String.charAt(Unknown Source) at

问题 This problem is related to String and array in Java. Say I have a String S= abcd. I have an array index[]={2}. My problem is to find out the value from String S at its index position 2 because array index[] hold 2. I have a target array which contain "EF". Now if S contain a at position 2 then it will replaced by "EF". How to access 2 position of S. Is it something like that. S[index[0]] Is this return S[2]? Example: Input: S = "abcd", indexes = [0,2], sources = ["a","cd"], targets = ["eee",