cell-array

Suppose I have a cell array x and an integer array y : x = {'apple', 'orange', 'banana', 'pear'}; y = [2 4 3 1]; In fact, y represents indices of x . I want to now create a cell array z with the elements of x reordered as specified by the order of these indices. This would give me: z = {'orange', 'pear', 'banana', 'apple'}; Can I do this in one line without having to loop through each element and place it in z in turn? z = x(y); Because StackOverflow requires answers at least 30 chars long, this sentence was created as a filler. That means: put in z the cell array with elements frrm x , that

I have a cell array: A = {NaN, ‘k’, ‘m’, ‘n’} I want to replace all but the 3rd element of A with NaNs to obtain B = {NaN, NaN, ‘m’, NaN} Please, any help/suggestions on how I could go about this? Also, is it possible to do this with a single line of code? You could create a new array of all NaN's and then replace the third element with the value from the initial cell array B = num2cell(nan(size(A)); B(3) = A(3); Alternately, you can overwrite the other values with: B = A; B([1 2 4]) = {NaN}; As far as a single line of code, the number of lines is quite irrelevant. What's important is

I have two cell arrays which may not be of the same size. Elements of cell arrays is randperm of an integer number. randperm data Type is double array. How can I find common elements of two cell arrays? For example: Q1 = {[1 2 3 4], [3 2 4 1], [4 2 1 3]} Q2 = {[2 4 3 1], [1 2 3 4], [1 2 4 3]} As I said elements of cell arrays are randperm . I want the output of above example be "Element-1 of Q1 i.e. [1 2 3 4] since it is also present in Q2 . Note: Cell Arrays may have different number of columns... Vertically concatenate the matrices inside the cell arrays and use intersect with the 'rows'

I have a function that takes variadic arguments. These arguments are parameter-value pairs, so varargin is a cell array in which every odd-indexed element is a string (the parameter), but the even-indexed elements can be a string, number, or cell array of strings. I want to find the index of a particular string in varargin . I have a working solution, but it uses arrayfun twice; is there a cleaner/faster/more effective way of find a string in such a cell array? The resulting index will be used to remove that element and the following one from varargin . I would like to minimize creation of new

Using this code but it keeps just giving me a 1x1 cell array mynewcellarray = mat2cell(oldmatrix, 50, 3) phyrox You should use num2cell : mynewcellarray=num2cell(oldmatrix) 来源： https://stackoverflow.com/questions/21336105/how-do-i-create-a-50x3-cell-array-from-a-50x3-matrix-keep-just-getting-a-1x1-ce

Imagine a function with a variable number of input arguments, alternately asking for a string and a value. myfunction('string1',value1,'string2',value2,...) e.g. myfunction('A',5,'B',10) I want to keep the ability to call the function like that and I dont want to change the evaluation of varargin inside the function. (Except ('string1','string2',...,value1,value2,...) if that helps) But I also have my input strings and values stored in a cell array inputvar <4x1 cell> : inputvar = 'A' [5] 'B' [10] Also this cell array has a variable length. My intention is to call my function somehow as