bytestring

问题 I just finished creating a huffman compression algorithm . I converted my compressed text from a string to a byte array with bytearray(). Im attempting to decompress my huffman algorithm. My only concern though is that i cannot convert my byte array back into a string. Is there any built in function i could use to convert my byte array (with a variable) back into a string? If not is there a better method to convert my compressed string to something else? I attempted to use byte_array.decode()

问题 I have code like this to convert hex into byte string (define (word->bin s) (let ((n (string->number s))) (bytes (bitwise-and (arithmetic-shift n -24) #xFF) (bitwise-and (arithmetic-shift n -16) #xFF) (bitwise-and (arithmetic-shift n -8) #xFF) (bitwise-and n #xFF)))) (word->bin "#x10000002") I'm thinking of a similar function to convert binary into integers, then print it. The end result is the binary translated to hex. Some helpful links: http://download.plt-scheme.org/doc/372/html/mzscheme

问题 For example given an arbitrary string. Could be chars or just random bytes : string = '\xf0\x9f\xa4\xb1' I want to output: b'\xf0\x9f\xa4\xb1' This seems so simple, but I could not find an answer anywhere. Of course just typing the b followed by the string will do. But I want to do this runtime, or from a variable containing the strings of byte. if the given string was AAAA or some known characters I can simply do string.encode('utf-8') , but I am expecting the string of bytes to just be

问题 I need to parse byte string which spans more than one line in the source code. Like this self.file.write(b'#compdef %s\n\n' '_arguments -s -A "-*" \\\n' % (self.cmdName,)) this line throws the following exception builtins.SyntaxError: cannot mix bytes and nonbytes literals which can be fixed in the following way self.file.write(b'#compdef %s\n\n\'\'_arguments -s -A "-*" \\\n' % (self.cmdName,)) Notice the backslashes after \n . but this fix does the follow the project rules of less than 79

问题 I am trying to adapt this AWS S3 upload code to handle Lazy ByteString where length is already known (so that it is not forced to be read in its entirety in memory - it comes over the network where length is sent beforehand). It seems I have to define a GivesPopper function over Lazy ByteString to convert it to RequestBodyStream. Because of the convoluted way GivesPopper is defined, I am not sure how to write it for Lazy ByteString . Will appreciate pointers on how to write it. Here is how it

问题 I'm attempting to use the encodeFile and decodeFile functions in Data.Binary to save a very large datastructure so that I don't have to recompute it every time I run this program. The relevant encoding- and decoding-functions are as follows: writePlan :: IO () writePlan = do (d, _, bs) <- return subjectDomain outHandle <- openFile "outputfile" WriteMode ((ebsP, aP), cacheData) <- preplanDomain d bs putStrLn "Calculated." let toWrite = ((map pseudofyOverEBS ebsP, aP), pseudofyOverMap cacheData

问题 I have a array of bytes in python (converted from an arbitrary text file) and would like to use those bytes as RGB values to store in an image. What is the best way to do this? thanks 回答1: That's kind of a late response but maybe it helps others in the future: Hopefully I interpreted your question right, but if your "arbitrary text file" represents the structure of an image file like ".jpg" you can just change the files extension from ".txt" to ".jpg" and import it with PIL for example. You

问题 I'm trying to modify the code shown far below, which works in Python 2.7.x, so it will also work unchanged in Python 3.x. However I'm encountering the following problem I can't solve in the first function, bin_to_float() as shown by the output below: float_to_bin(0.000000): '0' Traceback (most recent call last): File "binary-to-a-float-number.py", line 36, in <module> float = bin_to_float(binary) File "binary-to-a-float-number.py", line 9, in bin_to_float return struct.unpack('>d', bf)[0]

问题 I want to write a simple function which splits a ByteString into [ByteString] using '\n' as the delimiter. My attempt: import Data.ByteString listize :: ByteString -> [ByteString] listize xs = Data.ByteString.splitWith (=='\n') xs This throws an error because '\n' is a Char rather than a Word8 , which is what Data.ByteString.splitWith is expecting. How do I turn this simple character into a Word8 that ByteString will play with? 回答1: You could just use the numeric literal 10 , but if you want

问题 I've been making rather poor attempts at the PRIME1 problem on SPOJ. I discovered using that using ByteString really helped performance for reading in the problem text. However, using ByteString to write out the results is actually slightly slower than using Prelude functions. I'm trying to figure out if I'm doing it wrong, or if this is expected. I've conducted profiling and timing using (putStrLn.show) and the ByteString equivalents three different ways: I test each candidate to see if it