bytearrayoutputstream

I'm trying to capture the picture I'm getting from webview.capturePicture() to save it to an sqliteDatabase, to do I need to convert the image to a byte[] to be able to save it as a BLOB in my table, and then by able to retrieve that byte[] and convert it back to a bitmap. Here is what I'm doing: Picture p = webView.capturePicture(); ByteArrayOutputStream bos = new ByteArrayOutputStream(); p.writeToStream(bos); byte[] ba = bos.toByteArray()); I then retrieve the image by: byte[] image = cursor.getBlob(imageColumnIndex); Bitmap bm = BitmapFactory.decodeByteArray(image, 0, image.length); I'm

I read this post but I am not following. I have seen this but have not seen a proper example of converting a ByteArrayInputStream to String using a ByteArrayOutputStream . To retrieve the contents of a ByteArrayInputStream as a String , is using a ByteArrayOutputstream recommended or is there a more preferable way? I was considering this example and extend ByteArrayInputStream and utilize a Decorator to increase functionality at run time. Any interest in this being a better solution to employing a ByteArrayOutputStream ? A ByteArrayOutputStream can read from any InputStream and at the end

Is there any advantage in wrapping a BufferedOutputStream around a ByteArrayOutputStream instead of just using the ByteArrrayOutputStream by itself? Generally BufferedOutputStream wrapper is mostly used to avoid frequent disk or network writes. It can be much more expensive to separately write a lot of small pieces than make several rather large operations. The ByteArrayOutputStream operates in memory, so I think the wrapping is pointless. If you want to know the exact answer, try to create a simple performance-measuring application. Absolutely none. Though BufferedWriter and BufferedReader do

I've got a 40MB file in the disk and I need to "map" it into memory using a byte array. At first, I thought writing the file to a ByteArrayOutputStream would be the best way, but I find it takes about 160MB of heap space at some moment during the copy operation. Does somebody know a better way to do this without using three times the file size of RAM? Update: Thanks for your answers. I noticed I could reduce memory consumption a little telling ByteArrayOutputStream initial size to be a bit greater than the original file size (using the exact size with my code forces reallocation, got to check

I use aws-android-sdk-1.4.3/samples/S3_SimpleDB_SNS_SQS_Demo to preview my files stored on Amazon (Amazon Simple Storage Service). Looking through code I saw that they use this, to acces the files: com.amazonaws.demo.s3.S3.getDataForObject (line 130) public static String getDataForObject( String bucketName, String objectName ) { return read( getInstance().getObject( bucketName, objectName ).getObjectContent() ); } protected static String read( InputStream stream ) { try { ByteArrayOutputStream baos = new ByteArrayOutputStream( 8196 ); byte[] buffer = new byte[1024]; int length = 0; while ( (

I am supposed to develop a simple SFTP. Things were going fine until my ByteArrayOutputStream (in this case, baos ) was not writing all of the arrayByte . Can some please explain to me, why the system hangs on me? Server Side: public static void main (String[] args) { int portTexto = 5656; String comando; String regexGet = "\\s*(get)\\s[A-z0-9]*\\.[A-z0-9]*\\s*"; String regexPut = "\\s*(put)\\s[A-z0-9]*\\.[A-z0-9]*\\s*"; try{ ServerSocket servSockTexto = new ServerSocket(portTexto); // pegar IP de servidor. try { InetAddress addr = InetAddress.getLocalHost(); System.out.println(addr