buffered

How to read data (xml) sent by server if it doesn't send new line

£可爱£侵袭症+ 提交于 2019-12-12 02:52:04
问题 Let's say we try to communicate with a server (XMPP) which sends back XML data. We can use conn, err := net.Dial("tcp", s.Addr+":5222") //... r := bufio.NewReader(conn) //... s, err := s.R.ReadString(10) // to read a string But there is one problem that the server doesn't send the \10 (newline) symbol. I also tried 12 but without any luck. Same goes for readLine function as it also relies on \10. So how do I read the data sent by server? I tried using '>' as a delimiter and succeeded to

C++ buffered stream IO

冷暖自知 提交于 2019-12-09 03:20:18
问题 I understand that by default all stream IO supported by C++ is buffered. This means that data to be output is put into a buffer till it is full and then sent to the output device, similarly for input, the data is read once the buffer is empty...all this is done so that number of expensive system calls could be minimized. But how to verify this behavior in action. I mean consider the following code int main() { cout << "Hello world\n"; return 0 } Where does buffering come into picture here ? I

Is Stream.Read buffered when doing network I/O?

混江龙づ霸主 提交于 2019-12-07 16:52:01
问题 So I was recently doing some work, when somebody told me that if doing a Stream.Read on a network stream that is obtained from calling one of .NET's GetResponseStream on a WebResponse or those are buffered. He was saying that if you were to put a breakpoint, in the code where you're reading, you wouldn't stop the network traffic. I find that bizzare, but also hoping that it's true. How does that work? Is it even accurate? using (Stream webResponseStream = this.webResponse.GetResponseStream())

Is Stream.Read buffered when doing network I/O?

一个人想着一个人 提交于 2019-12-05 19:28:48
So I was recently doing some work, when somebody told me that if doing a Stream.Read on a network stream that is obtained from calling one of .NET's GetResponseStream on a WebResponse or those are buffered. He was saying that if you were to put a breakpoint, in the code where you're reading, you wouldn't stop the network traffic. I find that bizzare, but also hoping that it's true. How does that work? Is it even accurate? using (Stream webResponseStream = this.webResponse.GetResponseStream()) { byte[] readBuffer = new byte[bufferSize]; int bytesRead = webResponseStream.Read(readBuffer, 0,

Buffered Reader readLine() with Empty lines

放肆的年华 提交于 2019-12-04 06:26:06
I am using buffered reader to grab a line at a time from a text file. I am trying to also get the line number from the text file using a tracking integer. Unfortunately BufferedReader is skipping empty lines (ones with just /n or the carriage return). Is there a better way to solve this? Would using scanner work? Example code: int lineNumber = 0; while ((s = br.readLine()) != null) { this.charSequence.add(s, ++lineNumber); } polygenelubricants I could not reproduce your claim that BufferedReader skips empty lines; it should NOT have. Here are snippets to show that empty lines aren't just

C++ buffered stream IO

旧城冷巷雨未停 提交于 2019-12-01 08:34:34
I understand that by default all stream IO supported by C++ is buffered. This means that data to be output is put into a buffer till it is full and then sent to the output device, similarly for input, the data is read once the buffer is empty...all this is done so that number of expensive system calls could be minimized. But how to verify this behavior in action. I mean consider the following code int main() { cout << "Hello world\n"; return 0 } Where does buffering come into picture here ? I know there is buffering happening, but how to explain it? The output is seen instantly on the screen,

Buffered and unbuffered stream

99封情书 提交于 2019-11-30 15:44:10
In case of buffered stream it said in a book that it wait until the buffer is full to write back to the monitor. For example: cout << "hi"; What do they mean by "the buffer is full". cerr << "hi"; It is said in my book that everything sent to cerr is written to the standard error device immediately, what does it mean? char *ch; cin>> ch; // I typed "hello world"; In this example ch will be assigned to "hello" and "world" will be ignored does it mean that it still in the buffer and it will affect the results of future statements? Your book doesn't seem very helpful. 1) The output streams send

Efficient way of handling file pointers in Java? (Using BufferedReader with file pointer)

删除回忆录丶 提交于 2019-11-30 09:55:00
I have a log file which gets updated every second. I need to read the log file periodically, and once I do a read, I need to store the file pointer position at the end of the last line I read and in the next periodic read I should start from that point. Currently, I am using a random access file in Java and using the getFilePointer() method to get he offset value and the seek() method to go to the offset position. However, I have read in most articles and even the Java doc recommendations to use BufferredReader for efficient reading of a file. How can I achieve this (getting the filepointer

Understanding the Java stack

寵の児 提交于 2019-11-28 18:49:37
问题 There is this code: public class Main { public static void main(final String[] args) throws Exception { System.out.print("1"); doAnything(); System.out.println("2"); } private static void doAnything() { try { doAnything(); } catch (final Error e) { System.out.print("y"); } } } And there is the output: 1yyyyyyyy2 Why does it print "y" eight times and no more. How can Java call println() when StackOverflowError encountered? 回答1: Here you are catching Error and not Exception in which case your

Explanation for tiny reads (overlapped, buffered) outperforming large contiguous reads?

☆樱花仙子☆ 提交于 2019-11-27 18:35:58
(apologies for the somewhat lengthy intro) During development of an application which prefaults an entire large file (>400MB) into the buffer cache for speeding up the actual run later, I tested whether reading 4MB at a time still had any noticeable benefits over reading only 1MB chunks at a time. Surprisingly, the smaller requests actually turned out to be faster. This seemed counter-intuitive, so I ran a more extensive test. The buffer cache was purged before running the tests (just for laughs, I did one run with the file in the buffers, too. The buffer cache delivers upwards of 2GB/s