break

So, I am playing with force directed graph, and I've made that .text on my node changes on mouse over to another text from data. My code looks like this: script: var data = {"nodes":[ {"name":"YHO", "full_name":"Yahoo", "type":1, "slug": "www.yahoo.com", "entity":"company", "img_hrefD":"", "img_hrefL":""}, {"name":"GGL", "full_name":"Google", "type":2, "slug": "www.google.com", "entity":"company", "img_hrefD":"", "img_hrefL":""}, {"name":"BNG", "full_name":"Bing", "type":2, "slug": "www.bing.com", "entity":"company", "img_hrefD":"", "img_hrefL":""}, {"name":"YDX", "full_name":"Yandex", "type"

I have a python script that uses plt.show() as it's last instruction. When it runs, IDLE just hangs after the last instruction. I get the image but I don't get the prompt back. On other scripts I typically use ctrl-c to break the program (sometimes doesn't work immediately) but how do I get the prompt back with the plt.show() ? Ctrl-c doesn't work... Are there other ways to stop the program? This is IDLE on Windows, if it makes any difference. I have seen this problem with IDLE and matplotlib when using them on Windows. I don't know the exact cause, but Ctrl-c a couple times has typically

There is any way to do it like C/C# ? For example (C# style) for( int i=0; i<100; i++) { if(i==66) break; } Tomas Petricek The short answer is no. You would generally use some higher-order function to express the same functionality. There is a number of functions that let you do this, corresponding to different patterns (so if you describe what exactly you need, someone might give you a better answer). For example, tryFind function returns the first value from a sequence for which a given predicate returns true , which lets you write something like this: seq { 0 .. 100 } |> Seq.tryFind (fun i

Which statement will be executed after "continue" or "break" ? for(int i = 0; i < count; ++i) { // statement1 for(int j = 0; j < count; ++j) { //statement2 if(someTest) continue; } //statement3 } for(int i = 0; i < count; ++i) { // statement1 for(int j = 0; j < count; ++j) { //statement2 if(someTest) break; } //statement3 } Petar Ivanov continue: ++j and then if j < count then statement2 otherwise statement3 break: statement3 Continue jumps straight to the top of the innermost loop, where the per-iteration code and continuance check will be carried out (sections 3 and 2 of the for loop). Break

It appears I need to use a break in each case block in my switch statement using C#. I can see the reason for this in other languages where you can fall through to the next case statement. Is it possible for case blocks to fall through to other case blocks? Thanks very much, really appreciated! Guffa Yes, you can fall through to the next case block in two ways. You can use empty cases, which don't need a break, or you can use goto to jump to the next (or any) case: switch (n) { case 1: case 2: case 3: Console.WriteLine("1, 2 or 3"); goto case 4; case 4: Console.WriteLine(4); break; } The

输出某个英文文本文件中 26 字母出现的频率，由高到低排列，并显示字母出现的百分比，精确到小数点后面两位。 字母频率 = 这个字母出现的次数 / （所有A-Z，a-z字母出现的总数） 如果两个字母出现的频率一样，那么就按照字典序排列。 package Statistics; import java.io.File; import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; public class FileOutput { private static int[][] letter=new int[2][52]; public static void main(String[] args) throws IOException { StringBuilder sb = new StringBuilder(); File directory = new File("");//参数为空 String courseFile = directory.getCanonicalPath()+"/Harry Potter and the Sorcerer's Stone.txt"; BufferedReader bf = new BufferedReader(new

今日学习内容： 一、for 嵌套 例子一：输出九九乘法表 下面的图中： \t 表示一个tab键 例子二：输出 ****** ****** ****** 这中图案 for i in range(3): for j in range(6): print('*', end='') print() 一、for与break, for与continue 例子：0~15中，不打7和8以后的数字 for i in range(0, 16): if i == 7: continue # 跳过本次循环，不打印print 直接执行下一次循环 elif i == 9: break # i 等于9时 就结束for循环遍历。 print(i) # for循环正常执行结束，就会执行else对应的代码块 # 非正常结束，例如break打断，就不会执行代码结果 0 1 2 3 4 5 6 8 二、while 嵌套 和 break的使用 案例一：用户输入用户名，密码。若都输入正确，则显示登录成功，并结束输入。总共有三次输入机会，若三次都不正确，则显示登录失败，并结束输入。 实现方法一：count = 0 name = 'sean' word = '18' #这是整数int型。这里加引号 或者下面的输入 加int（） while count < 3: username = input('请输入您的用户名:')