bitstring | 易学教程

Elixir - find sub-bitstring within larger bitstring

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问题 How would I go about finding if a sub-bitstring is present with another bitstring in Elixir? I need to verify that bitstring X exists somewhere within bitstring Y for testing purposes. Is there a simple way to do this with existing functions? x = "bar" y = "foo bar baz" some_substring_function(x, y) with some_substring_function returning a truthy value. Thanks in advance! 回答1: You can use the =~ operator: iex> "hello world" =~ "hello" true The String module also has some convenience functions

LTE学习-MIB和SIB

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以下内容来自sharetechnote LTE学习 MIB（Master Information Block） SIB(System Information Block) MIB（Master Information Block） MIB每40毫秒传送一次，每10毫秒重复一次，携带以下信息： i) 下行带宽，发射天线个数 ii) System Frame Number(SFN) iii) PHICH配置 MIB ::= SEQUENCE { 下行带宽 ENUMERATED { n6, n15, n25, n50, n75, n100}, phich-配置, SFN BIT STRING (SIZE (8)), spare BIT STRING (SIZE (10)) } 可以通过解码MIB获得系统带宽和SFN。下面是MIB和SIB传输的周期： SIB(System Information Block) 随着LTE功能的发展，并开始与其他技术相互作用、融合(例如 wlan, V2X, NR等)，SIB的列表越来越长。现在最大的SIB类型号是SIB24。有些SIB对于初始的接入非常重要，在尝试附着到小区之前应该检测/解码它们。通常情况下，SIB的内容会根据情况进行修改，而UE也能够根据修改后的SIB进行更新。以下是目前完整的SIB列表： SIB 描述 SIB 1 小区选择,

python file I/O with binary data

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问题 I'm extracting jpeg type bits from mp3 data actually it will be album arts. I thought about using library called mutagen, but I'd like to try with bits for some practice purpose. import os import sys import re f = open(sys.argv[1], "rb") #sys.argv[1] gets mp3 file name ex) test1.mp3 saver = "" for value in f: for i in value: hexval = hex(ord(i))[2:] if (ord(i) == 0): saver += "00" #to match with hex form else: saver += hexval header = "ffd8" tail = "ffd9" this part of code is to get mp3 as

python file I/O with binary data

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Calculating Hamming weight efficiently in matlab

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问题 Given a MATLAB uint32 to be interpreted as a bit string, what is an efficient and concise way of counting how many nonzero bits are in the string? I have a working, naive approach which loops over the bits, but that's too slow for my needs. (A C++ implementation using std::bitset count() runs almost instantly). I've found a pretty nice page listing various bit counting techniques, but I'm hoping there is an easy MATLAB-esque way. http://graphics.stanford.edu/~seander/bithacks.html

Concatenating BitStrings (Not Binaries) in Erlang

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问题 How do you concatenate bitstrings. I mean bitstrings because I do not know the number of bytes to be a multiple of 8. A = <<3:2>> B = <<1:1>> C = <<15:4>> Solution should A|B|C should be <<127:7>> Thanks 回答1: Construct the binary using /bitstring and all the previous values. Here's an example, running in the erlang shell: 1> A = <<3:2>>. <<3:2>> 2> B = <<1:1>>. <<1:1>> 3> C = <<15:4>>. <<15:4>> 4> D = <<A/bitstring, B/bitstring, C/bitstring>>. <<127:7>> 来源： https://stackoverflow.com/questions

Convert binary (0|1) numpy to integer or binary-string?

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问题 Is there a shortcut to Convert binary (0|1) numpy array to integer or binary-string ? F.e. b = np.array([0,0,0,0,0,1,0,1]) => b is 5 np.packbits(b) works but only for 8 bit values ..if the numpy is 9 or more elements it generates 2 or more 8bit values. Another option would be to return a string of 0|1 ... What I currently do is : ba = bitarray() ba.pack(b.astype(np.bool).tostring()) #convert from bitarray 0|1 to integer result = int( ba.to01(), 2 ) which is ugly !!! 回答1: One way would be

What is the difference between a Binary and a Bitstring in Erlang?

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问题 In the Erlang shell, I can do the following: A = 300. 300 <<A:32>>. <<0, 0, 1, 44>> But when I try the following: B = term_to_binary({300}). <<131,104,1,98,0,0,1,44>> <<B:32>> ** exception error: bad argument <<B:64>> ** exception error: bad argument In the first case, I'm taking an integer and using the bitstring syntax to put it into a 32-bit field. That works as expected. In the second case, I'm using the term_to_binary BIF to turn the tuple into a binary, from which I attempt to unpack

Caching Matlab function results to file

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问题 I'm writing a simulation in Matlab. I will eventually run this simulation hundreds of times. In each simulation run, there are millions of simulation cycles. In each of these cycles, I calculate a very complex function, which takes ~0.5 sec to finish. The function input is a long bit array (>1000 bits) - which is an array of 0 and 1 . I hold the bit arrays in a matrix of 0 and 1 , and for each one of them I only run the function once - as I save the result in a different array (res) and check

Java Algoirthm number of Combinations of variables (Similar to Bit String Algoirthm)

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问题 I have a problem I'm trying to solve in Java and I cannot figure out the algorithm that I'm going to need to follow. This problem is similar to the Bit String problem (how many bit strings are there of length x), but with some added difficulty. I'm not even sure the algorithm for solving the normal bit string problem anyway. So here's my actual problem: I have 5 variables. Say Q W X Y Z. Each variable can take one of 3 values (so like bit string can take 1 or 0, but this can take say 0, 1, or