bitstring

I have some 256-character strings of hexadecimal characters which represent a sequence of bit flags, and I'm trying to convert them back into a bitstring so I can manipulate them with & , | , vec and the like. The hex strings are written in integer-wide big-endian groups, such that a group of 8 bytes like "76543210" should translate to the bitstring "\x10\x32\x54\x76" , i.e. the lowest 8 bits are 00001000 . The problem is that pack 's " h " format works on one byte of input at a time, rather than 8, so the results from just using it directly won't be in the right order. At the moment I'm doing

Is there a shortcut to Convert binary (0|1) numpy array to integer or binary-string ? F.e. b = np.array([0,0,0,0,0,1,0,1]) => b is 5 np.packbits(b) works but only for 8 bit values ..if the numpy is 9 or more elements it generates 2 or more 8bit values. Another option would be to return a string of 0|1 ... What I currently do is : ba = bitarray() ba.pack(b.astype(np.bool).tostring()) #convert from bitarray 0|1 to integer result = int( ba.to01(), 2 ) which is ugly !!! One way would be using dot-product with 2-powered range array - b.dot(2**np.arange(b.size)[::-1]) Sample run - In [95]: b = np

For an assignment, I'm doing a compression/decompression of Huffman algorithm in Visual Studio. After I get the 8 bits ( 10101010 for example) I want to convert it to a byte. This is the code I have: unsigned byte = 0; string stringof8 = "11100011"; for (unsigned b = 0; b != 8; b++){ if (b < stringof8.length()) byte |= (stringof8[b] & 1) << b; } outf.put(byte); First couple of bitstring are output correctly as a byte but then if I have more than 3 bytes being pushed I get the same byte multiple times. I'm not familiar with bit manipulation and was asking for someone to walk me through this or

I have a numpy array consisting of bitstrings and I intend to convert bitstrings to integer base 2 in order to perform some xor bitwise operations. I can convert string to integer with base 2 in python with this: int('000011000',2) I am wondering if there is a faster and better way to do this in numpy. An example of numpy array that I am working on is something like this: array([['0001'], ['0010']], dtype='|S4') and I expect to convert it to: array([[1],[2]]) Divakar One could use np.fromstring to separate out each of the string bits into uint8 type numerals and then use some maths with matrix

In the Erlang shell, I can do the following: A = 300. 300 <<A:32>>. <<0, 0, 1, 44>> But when I try the following: B = term_to_binary({300}). <<131,104,1,98,0,0,1,44>> <<B:32>> ** exception error: bad argument <<B:64>> ** exception error: bad argument In the first case, I'm taking an integer and using the bitstring syntax to put it into a 32-bit field. That works as expected. In the second case, I'm using the term_to_binary BIF to turn the tuple into a binary, from which I attempt to unpack certain bits using the bitstring syntax. Why does the first example work, but the second example fail? It