bit-manipulation

问题 I've been learning about adding two numbers using bit manipulation and I am having issues understanding how it is done in Python for negative numbers. For example, if I am trying to & the following: -0b1111010 (-122) & 0b11011110 (222) shouldn't it be: 0b1111010 & 0b11011110 ------------ 0b01011010 since only a combination of 1's results in 1's? Right now python gives 0b10000110 I couldn't find any resources specifically when a negative number is added to a positive number using python. 回答1:

问题 I've been learning about adding two numbers using bit manipulation and I am having issues understanding how it is done in Python for negative numbers. For example, if I am trying to & the following: -0b1111010 (-122) & 0b11011110 (222) shouldn't it be: 0b1111010 & 0b11011110 ------------ 0b01011010 since only a combination of 1's results in 1's? Right now python gives 0b10000110 I couldn't find any resources specifically when a negative number is added to a positive number using python. 回答1:

问题 I did not exactly understand what the "bitwise_and" operator does when used in openCV. I would also like to know about it's parameters. 回答1: bitwise_and Calculates the per-element bit-wise conjunction of two arrays or an array and a scalar. Parameters: src1 – first input array or a scalar. src2 – second input array or a scalar. src – single input array. value – scalar value. dst – output array that has the same size and type as the input arrays. mask – optional operation mask, 8-bit single

问题 I did not exactly understand what the "bitwise_and" operator does when used in openCV. I would also like to know about it's parameters. 回答1: bitwise_and Calculates the per-element bit-wise conjunction of two arrays or an array and a scalar. Parameters: src1 – first input array or a scalar. src2 – second input array or a scalar. src – single input array. value – scalar value. dst – output array that has the same size and type as the input arrays. mask – optional operation mask, 8-bit single

问题 I did not exactly understand what the "bitwise_and" operator does when used in openCV. I would also like to know about it's parameters. 回答1: bitwise_and Calculates the per-element bit-wise conjunction of two arrays or an array and a scalar. Parameters: src1 – first input array or a scalar. src2 – second input array or a scalar. src – single input array. value – scalar value. dst – output array that has the same size and type as the input arrays. mask – optional operation mask, 8-bit single

问题 I'm a little bit puzzled by the removal of enum flags to be perfectly honest. Let me make an example, let's say we have an enum that looks like this [Flags] enum Letter { A = 1, // 1 B = 2, // 10 C = 4 // 100 } Now if I want to make a variable hold the flags Letter.AB I could do foo = Letter.A | Letter.B . Now this makes sense to me, I can calculate this and it will make sense: 01 OR 10 = 11 = 3 = 1 + 2 = A + B = AB When it comes to removing flags, I am puzzled however, intuitively what I

问题 I'm a little bit puzzled by the removal of enum flags to be perfectly honest. Let me make an example, let's say we have an enum that looks like this [Flags] enum Letter { A = 1, // 1 B = 2, // 10 C = 4 // 100 } Now if I want to make a variable hold the flags Letter.AB I could do foo = Letter.A | Letter.B . Now this makes sense to me, I can calculate this and it will make sense: 01 OR 10 = 11 = 3 = 1 + 2 = A + B = AB When it comes to removing flags, I am puzzled however, intuitively what I

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: 64bit shift problem I'm using Visual Studio 2012 on Windows 8 64-bit, targeting x64 in debug mode, using an AMD Phenom II. So Basically... uint64_t Foo = 0xFFFFFFFFFFFFFFFF << 64;//Foo is now 0x0000000000000000 uint64_t Derp = 64; uint64_t Bar = 0xFFFFFFFFFFFFFFFF << Derp;//Foo is now 0xFFFFFFFFFFFFFFFF Using a lower value such as 63 restores normal behavior. Why is this happening and how can I get around it?

问题 I am currently working on a problem that wants me to build a subroutine that will reverse the bits in R16. 00000011 => 11000000 or 10101000 => 00010101 For the class we are using the AVR subset and the subroutine needs to work in norfair. This is what I have so far, any help would be appreciated! ldi r16,3 ;00000011 回答1: The naive solution is to loop through the bits with the shift operator and check. But be aware that AVR doesn't have a barrel shifter so it can only shift by 1, any other

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 days ago . found this question in geeksforgeeks related to dynamic programming with bitmasking : https://www.geeksforgeeks.org/sum-subsets-dynamic-programming/ I am trying for weeks but not able to understand how the answer is formulated. Please provide any links, that may help to understand