binary

问题 So I am quite new to Java and motivated to learn. This question might seem simple but I genuinely don't understand and have searched Google for answers (no luck). I am converting a decimal into Binary in Java. However, I thought representations of numbers are supposed to be given in data types int , double , and etc. The code is as follows : int decimal = 99; String binary = Integer.toBinaryString(decimal); System.out.println(binary); Why is it String binary , should it not be any of the

问题 So I am quite new to Java and motivated to learn. This question might seem simple but I genuinely don't understand and have searched Google for answers (no luck). I am converting a decimal into Binary in Java. However, I thought representations of numbers are supposed to be given in data types int , double , and etc. The code is as follows : int decimal = 99; String binary = Integer.toBinaryString(decimal); System.out.println(binary); Why is it String binary , should it not be any of the

问题 I wanted to convert an integer to binary string. I opted to use the native function that java allows Integer.toBinaryString(n) . But unfortunately, this trims the leading zero from my output. Lets say for example, I give the input as 18 , it gives me output of 10010 but the actual output is supposed to be 010010 . Is there a better/short-way to convert int to string than writing a user defined function? Or am I doing something wrong here? int n = scan.nextInt(); System.out.println(Integer

问题 I am trying to figure out how the imul and idiv instructions of the 8086 microprocessor work. I know this: 1. mul and div are multiplications and division for unsigned numbers 2. imul and idiv, are also multiplications and divisions but for signed numbers I searched all the web, and what I just wrote above, that's the only info that I've found, but written in different ways. I have this: mov AX, 0FFCEh idiv AH Because ah it's a byte, AL=AX/AH (the result) and AH=remainder After the

问题 I have the variable Number which is equal to "0b11001010" and I want it to be the type int like a normal binary is stored e.g. 0b11001010 Number = "0b11001010" NewNumber = 0b11001010 is there a really simple way and I am overlooking it? Thanks. 回答1: In python you can only create it as a binary value (as a syntactic sugar), it will be converted into an integer immediately. Try it for yourself: >>> 0b11001010 202 The same thing will happen with octal and hexadecimal values. So you can convert

问题 I`m trying to send binary file using socket. FILE *file; char *file_data; file = fopen(filepath, "rb"); //Allocate memory file_data=(char *)malloc(fileLen+1); //Read file contents into buffer fread(file_data, fileLen, 1, file); fclose(file); sent = send(client, file_data, strlen(header)+fileLen, 0); It works OK, but some files a too large and I want to read a part to buffer, send it, then read the second part, send it and so on. I tried to get parts using fread and fgets, but i failed =( How

问题 Here I am using sqlsrv : $conn = sqlsrv_connect("192.168.1.102,1433", array("Database"=>"RF_User", "UID"=>"rfo-gcp", "PWD" => "")); $tsql = "SELECT birthdate FROM tbl_rfaccount WHERE id = ?"; $stmt = sqlsrv_query($conn, $tsql, array("test")); $result = sqlsrv_fetch_array($stmt); var_dump($result); Result: array(2) { [0]=> object(DateTime)#1 (3) { ["date"]=> string(26) "2020-04-19 20:40:00.000000" ["timezone_type"]=> int(3) ["timezone"]=> string(3) "UTC" } ["birthdate"]=> object(DateTime)#1 (3

问题 Here I am using sqlsrv : $conn = sqlsrv_connect("192.168.1.102,1433", array("Database"=>"RF_User", "UID"=>"rfo-gcp", "PWD" => "")); $tsql = "SELECT birthdate FROM tbl_rfaccount WHERE id = ?"; $stmt = sqlsrv_query($conn, $tsql, array("test")); $result = sqlsrv_fetch_array($stmt); var_dump($result); Result: array(2) { [0]=> object(DateTime)#1 (3) { ["date"]=> string(26) "2020-04-19 20:40:00.000000" ["timezone_type"]=> int(3) ["timezone"]=> string(3) "UTC" } ["birthdate"]=> object(DateTime)#1 (3

问题 Here I am using sqlsrv : $conn = sqlsrv_connect("192.168.1.102,1433", array("Database"=>"RF_User", "UID"=>"rfo-gcp", "PWD" => "")); $tsql = "SELECT birthdate FROM tbl_rfaccount WHERE id = ?"; $stmt = sqlsrv_query($conn, $tsql, array("test")); $result = sqlsrv_fetch_array($stmt); var_dump($result); Result: array(2) { [0]=> object(DateTime)#1 (3) { ["date"]=> string(26) "2020-04-19 20:40:00.000000" ["timezone_type"]=> int(3) ["timezone"]=> string(3) "UTC" } ["birthdate"]=> object(DateTime)#1 (3

问题 Code is mostly done but my code is printing incorrectly its printing out as 110 as opposed to 011. The problem im doing requires to reverse the "110" to "011" import java.util.Scanner; public class LabProgram { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int num, binaryNum = 0; int i = 1, rem; num = scan.nextInt(); while (num != 0) { rem = num % 2; num /= 2; binaryNum += rem * i; i *= 10; } System.out.println(binaryNum); } } 回答1: Then use a string as