binary-search

问题 I was practising a questions on hackerearth : https://www.hackerearth.com/practice/algorithms/searching/binary-search/practice-problems/algorithm/monk-and-special-integer-code-monk/ In this question I had written a binary search code where I had used: int mid=(low+high)/2 My loop got stuck here and so I was getting TLE for some cases. Having realised the problem (that repeatedly low was being chosen) I changed the mid to low +(high-low+1)/2 and with this change whole test cases passed. (Code

问题 Given two arrays a and b of size n . I have to choose one element from a and two elements from b such that. a[i] * a[i] = b[j] * b[k] . I am able to find BruteForce in O(n^2 log(n)) traversing both the arrays and binary searching the value. But dont know how to improve it even more. How do I count all these number where elements range from 1 <= a[i] <= 10^6 and 1 <= n <= 10^6 . 回答1: Well, I can think in a O(n²) solution. unordered_multiset S = {} for each element B in b { S = S ∪ B } First of

问题 Given two arrays a and b of size n . I have to choose one element from a and two elements from b such that. a[i] * a[i] = b[j] * b[k] . I am able to find BruteForce in O(n^2 log(n)) traversing both the arrays and binary searching the value. But dont know how to improve it even more. How do I count all these number where elements range from 1 <= a[i] <= 10^6 and 1 <= n <= 10^6 . 回答1: Well, I can think in a O(n²) solution. unordered_multiset S = {} for each element B in b { S = S ∪ B } First of

问题 The naive binary search is a very efficient algorithm: you take the midpoint of your high and low points in a sorted array and adjust your high or low point accordingly. Then you recalculate your endpoint and iterate until you find your target value (or you don't, of course.) Now, quite clearly, if you don't use the midpoint, you introduce some risk to the system. Let's say you shift your search target away from the midpoint and you create two sides - I'll call them a big side and small side.

问题 Good day! I have a List of ValueObj: class ValueObj { int ID; float value; } How to get binary search objects by id? (List tempValues) I make ValueComparer class,but dont know am i right? class ValueComparer<ValueObj> { public int Compare(ValueObjx, ValueObjy) { if (x == y) return 0; if (x == null) return -1; if (y == null) return 1; return -1; ///??? } } I need to sort List by ID. Like that?: tempValues.Sort(new ValueComparer()); And how to use BinarySearch? 回答1: The List class in C# has a

问题 Good day! I have a List of ValueObj: class ValueObj { int ID; float value; } How to get binary search objects by id? (List tempValues) I make ValueComparer class,but dont know am i right? class ValueComparer<ValueObj> { public int Compare(ValueObjx, ValueObjy) { if (x == y) return 0; if (x == null) return -1; if (y == null) return 1; return -1; ///??? } } I need to sort List by ID. Like that?: tempValues.Sort(new ValueComparer()); And how to use BinarySearch? 回答1: The List class in C# has a

问题 I have this code to binary search. public class BinarySearch { private static int location; private static int a = 14; static int[] numbers = new int[]{3, 6, 7, 11, 14, 16, 20, 45, 68, 79}; public static int B_Search(int[] sortedArray, int key) { int lowB = 0; int upB = sortedArray.length; int mid; while (lowB < upB) { mid = (lowB + upB) / 2; if (key < sortedArray[mid]) { upB = mid - 1; } else if (key > sortedArray[mid]) { lowB = mid + 1; } else { return mid; } } return -1; } public static

问题 I have this code to binary search. public class BinarySearch { private static int location; private static int a = 14; static int[] numbers = new int[]{3, 6, 7, 11, 14, 16, 20, 45, 68, 79}; public static int B_Search(int[] sortedArray, int key) { int lowB = 0; int upB = sortedArray.length; int mid; while (lowB < upB) { mid = (lowB + upB) / 2; if (key < sortedArray[mid]) { upB = mid - 1; } else if (key > sortedArray[mid]) { lowB = mid + 1; } else { return mid; } } return -1; } public static

问题 I have this code to binary search. public class BinarySearch { private static int location; private static int a = 14; static int[] numbers = new int[]{3, 6, 7, 11, 14, 16, 20, 45, 68, 79}; public static int B_Search(int[] sortedArray, int key) { int lowB = 0; int upB = sortedArray.length; int mid; while (lowB < upB) { mid = (lowB + upB) / 2; if (key < sortedArray[mid]) { upB = mid - 1; } else if (key > sortedArray[mid]) { lowB = mid + 1; } else { return mid; } } return -1; } public static

问题 I know this is a very famous question and lots of answers provided already, but I am trying to implement binary search algorithm in java of my own. First of all getting following compilation error, why?? This method must return a result of type int Second how this approach differs from this famous solution public static int binarySearch(int test[], int num){ int midLength = test.length/2; int fullLength = test.length; if(num > test[midLength]){ int newArray[] = new int[fullLength - midLength]