binary-search-tree

How to print elements from Binary Tree by level in c [closed]

半世苍凉 提交于 2020-08-05 07:03:12
问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 4 years ago . Improve this question I got binary tree, not BST, so elements are not sorted, and information that every node holds is string type. When I am printing elements that hold integers in BST I do it with recursion like this: (in_order printing) void PrintElements(const Data* node) { // Check if its

Dynamic Programming: Why Knuth's improvement to Optimal Binary Search Tree O(n^2)?

主宰稳场 提交于 2020-07-17 06:30:53
问题 This is Exercise 15.5-4 of Introduction to Algorithms, 3rd edition, which is about Knuth's improvement to the DP approach to Optimal Binary Search Tree. The DP algorithm of Optimal Binary Search Tree is: OPTIMAL_BST(p, q, n) let e[1..n+1, 0..n], w[1..n+1, 0..n], and root[1..n, 1..n] be new tables for i = 1 to n+1 e[i, i - 1] = q[i - 1]; w[i, i - 1] = q[i - 1]; for l = 1 to n for i = 1 to n - l + 1 j = i + l - 1 e[i, j] = INFINITY w[i, j] = w[i, j - 1] + p[j] + q[j] for r = i to j t = e[i, r -

Dynamic Programming: Why Knuth's improvement to Optimal Binary Search Tree O(n^2)?

强颜欢笑 提交于 2020-07-17 06:30:47
问题 This is Exercise 15.5-4 of Introduction to Algorithms, 3rd edition, which is about Knuth's improvement to the DP approach to Optimal Binary Search Tree. The DP algorithm of Optimal Binary Search Tree is: OPTIMAL_BST(p, q, n) let e[1..n+1, 0..n], w[1..n+1, 0..n], and root[1..n, 1..n] be new tables for i = 1 to n+1 e[i, i - 1] = q[i - 1]; w[i, i - 1] = q[i - 1]; for l = 1 to n for i = 1 to n - l + 1 j = i + l - 1 e[i, j] = INFINITY w[i, j] = w[i, j - 1] + p[j] + q[j] for r = i to j t = e[i, r -

Turning a Binary Tree to a sorted array

眉间皱痕 提交于 2020-06-27 11:12:34
问题 Is there a way to turn a Binary to a sorted array without having to traverse the tree for every array index? Node root; Node runner; int current_smallest; void findsmallest(Node root){ //Pre-order traversal if(root == null){ return; }else{ runner = root; if(current_smallest == null){ current_smallest = runner.element; }else{ if(current_smallest > runner.element){ current_smallest = runner.element; } } findsmallest(runner.left); findsmallest(runner.right); } } void fill_array( int [] array ){

Writing Backtrack method for a new class implementing Binary Search Tree

旧街凉风 提交于 2020-06-17 09:45:08
问题 I'm trying to implement the backtrack method on a new class named BacktrackingBST, which consists of the root node of a Binary Search Tree and a stack. the stack is used to store inserted or deleted nodes from the tree in order to allow us to backtrack said methods. i encounter an issue while trying to backtrack deletion , the problem was that while i was to restore the deleted node back to its original place i failed to come up with a solution on how to get the new node in its place like its

deleting a node from a binary search tree using recursion

点点圈 提交于 2020-06-17 09:10:02
问题 So I'm trying to delete a node from a tree by using these two functions inside the class.Unfortunately it just doesnt delete anything and i was wondering what is wrong about it! any help would be truly appreciated. def Find_Min(self,node): current=node while current.left is None: current=current.left return current def deletenode(self,node,ntbd): ##ntbd:node to be deleted /// node: root node if node is None: return None elif node.data>ntbd: node.left=self.deletenode(node.left,ntbd) elif node

deleting a node from a binary search tree using recursion

筅森魡賤 提交于 2020-06-17 09:09:33
问题 So I'm trying to delete a node from a tree by using these two functions inside the class.Unfortunately it just doesnt delete anything and i was wondering what is wrong about it! any help would be truly appreciated. def Find_Min(self,node): current=node while current.left is None: current=current.left return current def deletenode(self,node,ntbd): ##ntbd:node to be deleted /// node: root node if node is None: return None elif node.data>ntbd: node.left=self.deletenode(node.left,ntbd) elif node

backtrack Binary Search Tree

ぃ、小莉子 提交于 2020-06-01 06:04:32
问题 I'm trying to implement the backtrack method on a new class named BacktrackingBST, which consists of the root node of a Binary Search Tree and a stack. the stack is used to store inserted or deleted nodes from the tree in order to allow us to backtrack said methods. i encounter an issue while trying to backtrack deletion , the problem was that while i was to restore the deleted node back to its original place i failed to come up with a solution on how to get the new node in its place like its

backtrack Binary Search Tree

断了今生、忘了曾经 提交于 2020-06-01 06:03:59
问题 I'm trying to implement the backtrack method on a new class named BacktrackingBST, which consists of the root node of a Binary Search Tree and a stack. the stack is used to store inserted or deleted nodes from the tree in order to allow us to backtrack said methods. i encounter an issue while trying to backtrack deletion , the problem was that while i was to restore the deleted node back to its original place i failed to come up with a solution on how to get the new node in its place like its

How to traverse a binary search tree in alphabetical order python? [closed]

和自甴很熟 提交于 2020-05-24 06:08:21
问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 19 days ago . I need your help or if you can give me advice. I'm really struggling and some help would be perfect, so this is what I got so far; import BST, TreeNode class Bibliography: def __init__(self): self.bibtree = BST() def getReference(self,key): """Return the reference for the key, if it exists,