assignment-operator

Python assignment operator differs from non assignment

早过忘川 提交于 2020-12-25 00:35:43
问题 I have face this weird behavior I can not find explications about. MWE: l = [1] l += {'a': 2} l [1, 'a'] l + {'B': 3} Traceback (most recent call last): File "<input>", line 1, in <module> TypeError: can only concatenate list (not "dict") to list Basically, when I += python does not raise an error and append the key to the list while when I only compute the + I get the expected TypeError . Note: this is Python 3.6.10 回答1: l += ... is actually calling object.__iadd__(self, other) and modifies

Python assignment operator differs from non assignment

时光怂恿深爱的人放手 提交于 2020-12-25 00:34:33
问题 I have face this weird behavior I can not find explications about. MWE: l = [1] l += {'a': 2} l [1, 'a'] l + {'B': 3} Traceback (most recent call last): File "<input>", line 1, in <module> TypeError: can only concatenate list (not "dict") to list Basically, when I += python does not raise an error and append the key to the list while when I only compute the + I get the expected TypeError . Note: this is Python 3.6.10 回答1: l += ... is actually calling object.__iadd__(self, other) and modifies

Python assignment operator differs from non assignment

给你一囗甜甜゛ 提交于 2020-12-25 00:31:58
问题 I have face this weird behavior I can not find explications about. MWE: l = [1] l += {'a': 2} l [1, 'a'] l + {'B': 3} Traceback (most recent call last): File "<input>", line 1, in <module> TypeError: can only concatenate list (not "dict") to list Basically, when I += python does not raise an error and append the key to the list while when I only compute the + I get the expected TypeError . Note: this is Python 3.6.10 回答1: l += ... is actually calling object.__iadd__(self, other) and modifies

Python assignment operator differs from non assignment

£可爱£侵袭症+ 提交于 2020-12-25 00:30:31
问题 I have face this weird behavior I can not find explications about. MWE: l = [1] l += {'a': 2} l [1, 'a'] l + {'B': 3} Traceback (most recent call last): File "<input>", line 1, in <module> TypeError: can only concatenate list (not "dict") to list Basically, when I += python does not raise an error and append the key to the list while when I only compute the + I get the expected TypeError . Note: this is Python 3.6.10 回答1: l += ... is actually calling object.__iadd__(self, other) and modifies

Python assignment operator differs from non assignment

Deadly 提交于 2020-12-25 00:30:27
问题 I have face this weird behavior I can not find explications about. MWE: l = [1] l += {'a': 2} l [1, 'a'] l + {'B': 3} Traceback (most recent call last): File "<input>", line 1, in <module> TypeError: can only concatenate list (not "dict") to list Basically, when I += python does not raise an error and append the key to the list while when I only compute the + I get the expected TypeError . Note: this is Python 3.6.10 回答1: l += ... is actually calling object.__iadd__(self, other) and modifies

How the assignment statement in an if statement serves as a condition?

北战南征 提交于 2020-11-29 10:27:42
问题 if ((vnd = (struct diam_vnd_t *)g_hash_table_lookup(vendors,vend))) {...} Can you tell me why it is an assignment but not a boolean expression in the brackets ? And in what situation this assignment can be considered "true" or "false" ? 回答1: Quoting C11 , chapter §6.5.16, Assignment operators ( emphasis mine ) An assignment operator stores a value in the object designated by the left operand. An assignment expression has the value of the left operand after the assignment, 111) but is not an

How the assignment statement in an if statement serves as a condition?

廉价感情. 提交于 2020-11-29 10:26:25
问题 if ((vnd = (struct diam_vnd_t *)g_hash_table_lookup(vendors,vend))) {...} Can you tell me why it is an assignment but not a boolean expression in the brackets ? And in what situation this assignment can be considered "true" or "false" ? 回答1: Quoting C11 , chapter §6.5.16, Assignment operators ( emphasis mine ) An assignment operator stores a value in the object designated by the left operand. An assignment expression has the value of the left operand after the assignment, 111) but is not an

How to compare a char?

北城以北 提交于 2020-11-26 06:41:08
问题 I am learning c. I have a question. Why doesn't my program work? #include<stdio.h> #include<conio.h> #include<stdlib.h> char cmd; void exec() { if (cmd == "e") { printf("%c", cmd); // exit(0); } else { printf("Illegal Arg"); } } void input() { scanf("%c", &cmd); exec(); } int main() { input(); return 0; } I insert a "e" but it says illegal arg. cmd is not equal to "e". Why? I set cmd with scanf to "e". 回答1: First of, in C single quotes are char literals, and double quotes are string literals.