array-splice | 易学教程

Merge array into established array at random indexes in PHP

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问题 I'm building an image gallery and want to throw some promo banners in at random points to promote certain offers to users. Given the following two arrays have been filtered from a database query: Media images array: Array ( [0] => Array ( [insertDate] => 2014-11-10 11:22:58 [keyword] => standard [mediaClass] => image [mediaURL] => http://image1.jpg [promoURL] => ) [2] => Array ( [insertDate] => 2014-11-10 11:23:18 [keyword] => standard [mediaClass] => image [mediaURL] => http://image3.jpg

Will emptying an Array = [ ] cause memory leak?

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问题 Hey guys I was wondering if removing all objects on the stage like so: //bomb for each (var bomb:mcBomb in aBombArray) { bomb.parent.removeChild(bomb); aBombArray = []; bomb = null; } at the end of the game cause a Memory Leak? Is this removing all objects in the array and setting it back to 0? Should I instead use aBombArray.length = 0; ? I have all my arrays removed like this at the end of the game. I notice that when you get the 'Game Over' screen the memory doesn't decrease it instead

Javascript “shift” versus “splice” - are these statements equal?

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问题 I just want to confirm if the following two Javascript statements produces the same results, as it seems to me: First: var element = my_array.splice(0,1)[0]; Second: var element = my_array.shift(); I want to substitute the first by the second, in my own code, to improve readability. Can I do this? 回答1: They will have the same effect, yes. splice(0, 1) will remove the first element from my_array and return a new array containing that element. shift will do the same, but return the element

array_splice() - Numerical Offsets of Associative Arrays

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I'm trying to do something but I can't find any solution, I'm also having some trouble putting it into works so here is a sample code, maybe it'll be enough to demonstrate what I'm aiming for: $input = array ( 'who' => 'me', 'what' => 'car', 'more' => 'car', 'when' => 'today', ); Now, I want to use array_splice() to remove (and return) one element from the array: $spliced = key(array_splice($input, 2, 1)); // I'm only interested in the key... The above will remove and return 1 element (third argument) from $input (first argument), at offset 2 (second argument), so $spliced will hold the value

Javascript “shift” versus “splice” - are these statements equal?

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I just want to confirm if the following two Javascript statements produces the same results, as it seems to me: First: var element = my_array.splice(0,1)[0]; Second: var element = my_array.shift(); I want to substitute the first by the second, in my own code, to improve readability. Can I do this? They will have the same effect, yes. splice(0, 1) will remove the first element from my_array and return a new array containing that element. shift will do the same, but return the element itself, not an array. shift is more readable (in my opinion) and is also significantly faster (in Chrome at

angularjs forEach and splice

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问题 I have an array like this: $scope.emails = [ {"key":"Work","value":"user@domine.com"}, {"key":"","value":""}, {"key":"Work","value":"user2@domine.com"} {"key":"","value":""}]; So, I want to remove empty emails but angular forEach method removing only one object that is last object why???. js code angular.forEach($scope.emails, function(email, index){ if(email.value ===""){ $scope.emails.splice(index, 1); } }); where I am doing wrong JS Bin 回答1: The problem is that you remove elements from the

How to splice an array to insert array at specific position?

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问题 $custom = Array( Array( 'name' => $name1, 'url' => $url1 ), Array( 'name' => $name_a, 'url' => $url_a ) ); I am attempting to splice the array with the following: $bread_elem = array('name' => 'Golf', 'url' => $slug . $parent_slug); array_splice($custom, 1, 0, $bread_elem); I want my array to become the following, with the value of $sale_bread_elem inserted into position one within the array. I can't see what I am doing wrong. $custom = Array( Array( 'name' => $name1, 'url' => $url1 ), Array(

Is there a way to use Array.splice in javascript with the third parameter as an array?

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I'm attempting the following: var a1 = ['a', 'e', 'f']; // [a, e, f] var a2 = ['b', 'c', 'd']; // [b, c, d] a1.splice(1, 0, a2); // expected [a, b, c, d, e, f] // actual (a, [b, c, d], e, f] I am confined in my use case by having a2 exist as an array of indeterminant size. Does anyone know of a way to feed splice an array as the substitution, or alternatively a built-in function to do this? I know I could iterate over the elements of a2 and splice them in one at a time, but I'd prefer the fastest method possible because I will need to do this a lot. Array.splice supports multiple arguments

Is there a way to use Array.splice in javascript with the third parameter as an array?

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问题 I'm attempting the following: var a1 = ['a', 'e', 'f']; // [a, e, f] var a2 = ['b', 'c', 'd']; // [b, c, d] a1.splice(1, 0, a2); // expected [a, b, c, d, e, f] // actual (a, [b, c, d], e, f] I am confined in my use case by having a2 exist as an array of indeterminant size. Does anyone know of a way to feed splice an array as the substitution, or alternatively a built-in function to do this? I know I could iterate over the elements of a2 and splice them in one at a time, but I'd prefer the

Best way to delete “column” from multidimensional array

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I have a multidimensional php array that represents a table like this ------------- | A | 0 | A | |---|---|---| | 0 | 0 | 0 | |---|---|---| | A | 0 | A | ------------- so the array looks like this: array (size=3) 0 => array (size=3) 0 => string 'A' (length=1) 1 => string '0' (length=1) 2 => string 'A' (length=1) 1 => array (size=3) 0 => string '0' (length=1) 1 => string '0' (length=1) 2 => string '0' (length=1) 2 => array (size=3) 0 => string 'A' (length=1) 1 => string '0' (length=1) 2 => string 'A' (length=1) Now i want to delete the second row and the second column (this is just a simplified