array-difference

Identifying differences between groups in pandas dataframe

旧时模样 提交于 2019-12-12 19:12:26
问题 I have a pandas dataframe indexed by date and and ID. I would like to: Identify the ID of additions and deletions between dates Add the ID to another dataframe with the date of the addition/deletion. date ID value 12/31/2010 13 -0.124409 9 0.555959 1 -0.705634 2 -3.123603 4 0.725009 1/31/2011 13 0.471078 9 0.276006 1 -0.468463 22 1.076821 11 0.668599 Desired output: date ID flag 1/31/2011 22 addition 1/31/2011 11 addition 1/31/2011 2 deletion 1/31/2011 4 deletion I have tried Diff between two

PHP: Case-insensitive “array_diff”

纵然是瞬间 提交于 2019-12-12 07:44:00
问题 I have following two arrays and the code to find array_diff: $obs_ws = array("you", "your", "may", "me", "my", "etc"); $all_ws = array("LOVE", "World", "Your", "my", "etc", "CoDe"); $final_ws = array_diff($all_ws, $obs_ws); Above code giving output array as: $final_ws = array("LOVE", "World", "Your", "CoDe"); But I want it as: $final_ws = array("LOVE", "World", "CoDe"); Note "Your" is not removed, it may be due to "Y" is in caps in second array. I want to exclude "Your" also, so is there any

Ruby: How to find difference between 2 arrays, order matters

橙三吉。 提交于 2019-12-10 17:15:46
问题 I'm trying to count the differences between two arrays where the order DOES matter. For example: array_one = ["A", "B", "C"] array_two = ["B", "C", "A"] This would yield 3 differences because: array_one[0] != array_two[0] array_one[1] != array_two[1] array_one[2] != array_two[2] Another example: array_one = ["Z", "X", "Y"] array_two = ["Z", "W", "Y"] This would yield 1 because: array_one[0] == array_two[0] array_one[1] != array_two[1] array_one[2] == array_two[2] Any suggestions greatly

Behavior of array_diff_uassoc not clear

六眼飞鱼酱① 提交于 2019-12-10 14:53:53
问题 First of all I need to mention that I digged into manual and php docs and didnt find an answer. Here's a code I use: class chomik { public $state = 'normal'; public $name = 'no name'; public function __construct($name) { $this->name = $name; } public function __toString() { return $this->name . " - " . $this->state; } } function compare($a, $b) { echo("$a : $b<br/>"); if($a != $b) { return 0; } else return 1; } $chomik = new chomik('a'); $a = array(5, $chomik, $chomik, $chomik); $b = array(

Difference between two numpy arrays in python

喜欢而已 提交于 2019-12-09 02:27:38
问题 I have two arrays, for example: array1=numpy.array([1.1, 2.2, 3.3]) array2=numpy.array([1, 2, 3]) How can I find the difference between these two arrays in Python, to give: [0.1, 0.2, 0.3] As an array as well? Sorry if this is an amateur question - but any help would be greatly appreciated! 回答1: This is pretty simple with numpy , just subtract the arrays: diffs = array1 - array2 I get: diffs == array([ 0.1, 0.2, 0.3]) 回答2: You can also use numpy.subtract It has the advantage over the

How to tell if a value changed over dimension(s) in Pandas

时间秒杀一切 提交于 2019-12-08 05:13:41
问题 Let's say that I have some customer data over some dates and I want to see if for example their address has changed. Over those dates. Ideally, i'd like to copy the two columns where the changes occurred into a new table or just get a metric for the amount of total changes. So, if I had a table like Date , Customer , Address 12/31/14, Cust1, 12 Rocky Hill Rd 12/31/15, Cust1, 12 Rocky Hill Rd 12/31/16, Cust1, 14 Rocky Hill Rd 12/31/14, Cust2, 12 Testing Rd 12/31/15, Cust2, 12 Testing Ln 12/31

array_udiff seems not work

只愿长相守 提交于 2019-12-07 15:55:25
I'm trying to compare two array with array_udiff, but it's very weired. it seems array_udiff not get the right answer. Here is the live demo . The result should be an empty array, but leave one element unfiltered out. <?php $string = '{ "sakiniai": [ { "Faktas": "A", "value": "true" }, { "Faktas": "B", "value": "true" }, { "Faktas": "A", "value": "false" } ] }'; $sakiniais = json_decode($string, true)['sakiniai']; $v = $sakiniais[0]; $arr[] = $v; $v['value'] = $v['value'] == "true" ? "false" : "true"; $arr[] = $v; var_dump($arr); var_dump($sakiniais); print_r(array_udiff($arr, $sakiniais,

Python numpy subtraction no negative numbers (4-6 gives 254)

一个人想着一个人 提交于 2019-12-05 17:24:48
问题 I wish to subtract 2 gray human faces from each other to see the difference, but I encounter a problem that subtracting e.g. [4] - [6] gives [254] instead of [-2] (or difference: [2]). print(type(face)) #<type 'numpy.ndarray'> print(face.shape) #(270, 270) print(type(nface)) #<type 'numpy.ndarray'> print(nface.shape) #(270, 270) #This is what I want to do: sface = face - self.nface #or sface = np.subtract(face, self.nface) Both don't give negative numbers but instead subtract the rest after 0

Python numpy subtraction no negative numbers (4-6 gives 254)

戏子无情 提交于 2019-12-04 02:10:22
I wish to subtract 2 gray human faces from each other to see the difference, but I encounter a problem that subtracting e.g. [4] - [6] gives [254] instead of [-2] (or difference: [2]). print(type(face)) #<type 'numpy.ndarray'> print(face.shape) #(270, 270) print(type(nface)) #<type 'numpy.ndarray'> print(nface.shape) #(270, 270) #This is what I want to do: sface = face - self.nface #or sface = np.subtract(face, self.nface) Both don't give negative numbers but instead subtract the rest after 0 from 255. Output example of sface: [[ 8 255 8 ..., 0 252 3] [ 24 18 14 ..., 255 254 254] [ 12 12 12 ..

PHP: Case-insensitive “array_diff”

廉价感情. 提交于 2019-12-03 11:34:52
I have following two arrays and the code to find array_diff: $obs_ws = array("you", "your", "may", "me", "my", "etc"); $all_ws = array("LOVE", "World", "Your", "my", "etc", "CoDe"); $final_ws = array_diff($all_ws, $obs_ws); Above code giving output array as: $final_ws = array("LOVE", "World", "Your", "CoDe"); But I want it as: $final_ws = array("LOVE", "World", "CoDe"); Note "Your" is not removed, it may be due to "Y" is in caps in second array. I want to exclude "Your" also, so is there any case-insensitive version of array_diff in PHP. I tried array_udiff but I am not getting exactly how to