Multiple pairwise differences based on column name patterns
来源： https://stackoverflow.com/questions/62043917/multiple-pairwise-differences-based-on-column-name-patterns
array-difference
Multiple pairwise differences based on column name patterns
来源： https://stackoverflow.com/questions/62043917/multiple-pairwise-differences-based-on-column-name-patterns
Multiple pairwise differences based on column name patterns
来源： https://stackoverflow.com/questions/62043917/multiple-pairwise-differences-based-on-column-name-patterns
PHP remove array items from another if exists [duplicate]
问题 This question already has answers here : PHP get difference of two arrays of objects (3 answers) Closed 2 years ago . I have 2 object arrays: Array A and Array B. how can I check if object from Array B exists in Array A. and if exists remove it from Array A. Example: Array A: [ {"id": 1, "name": "item1"}, {"id": 2, "name": "item2"}, {"id": 3, "name": "item3"}, {"id": 4, "name": "item4"} ] Array B [ {"id": 1, "name": "item1"}, {"id": 3, "name": "item3"} ] After removing Array A should look
PHP: How to compare keys in one array with values in another, and return matches?
问题 I have the following two arrays: $array_one = array('colorZero'=>'black', 'colorOne'=>'red', 'colorTwo'=>'green', 'colorThree'=>'blue', 'colorFour'=>'purple', 'colorFive'=>'golden'); $array_two = array('colorOne', 'colorTwo', 'colorThree'); I want an array from $array_one which only contains the key-value pairs whose keys are members of $array_two (either by making a new array or removing the rest of the elements from $array_one ) How can I do that? I looked into array_diff and array
Diffing two Observables
问题 I'm looking for a best way to Diff two Observables. Filtered values from ObservableA should be emited as soon as ObservableB completes without waiting for ObservableA to complete. <html> <head> <title></title> <script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/5.3.0/Rx.js"></script> <script> const observable_a = Rx.Observable.interval(2000).take(10);//0,1,2,3,4,5,6,7,8,9 const observable_b = Rx.Observable.interval(1000).map(x=>x+3).take(5);//3,4,5,6,7 someDiffObservable(observable_a
C: Print only not common elements in 2 arrays
问题 I have some C code I want to modify really simple. Let's say I have two arrays like this int v1[5] = {1, 3, 7, 13, 10}; int v2[2] = {1, 10}; And I would like to print the not common elements (difference) like: 3, 7, 13 Here is my attempt which is not enough yet: #include <stdio.h> int main() { int v1[5] = { 1, 3, 7, 13, 10 }; int v2[2] = { 1, 10 }; for (int i = 0; i < sizeof(v1) / (sizeof * v1); i++) { for (int j = 0; j < sizeof(v2) / (sizeof * v2); j++) { if (v1[i] != v2[j]) { printf("%d ",
array_udiff seems not work
问题 I'm trying to compare two array with array_udiff, but it's very weired. it seems array_udiff not get the right answer. Here is the live demo. The result should be an empty array, but leave one element unfiltered out. <?php $string = '{ "sakiniai": [ { "Faktas": "A", "value": "true" }, { "Faktas": "B", "value": "true" }, { "Faktas": "A", "value": "false" } ] }'; $sakiniais = json_decode($string, true)['sakiniai']; $v = $sakiniais[0]; $arr[] = $v; $v['value'] = $v['value'] == "true" ? "false" :
PHP compare Arrray1 with Array2 and find difference. Then Fill the missing values of Array1 with zero's
问题 Issue: Draw checkboxes and assign ID from query1 to elementId and values assigned to checkbox from query2. But the issue is query 2 not always returns full 9 values as compared to array1. And I want to replace missing values in query 2 with zero's after comparing the array1 values. My Approach: Get result set of two queries and query 1 resultset = $tresult; query 1 resultset = $assignedTiles; $a1 = array(); while ($row = mysql_fetch_row($tresult)){ $a1[] = $row; } $a2 = array(); if (mysql_num
Finding the difference between two values in a numpy array
问题 I have a numpy list which I initiate by (my_array=[] and has a shape of (0,)) then I append the wm and hm elements to it like so(r is a cascade with the format of-[[300 240 22 22]]): my_array=[] for (x, y, w, h) in r: wm=int(x+ (w/2.)) hm=int(y+ (h/2.)) my_array.append([numpy.float32(wm), numpy.float32(hm)]) return numpy.array(my_array) That code produces: wm element the hm element [[270.01 303.43] [310.17 306.37]] # second to last row [[269.82 303.38] [310.99 306.86]] # the last row the