argv

I'm reading learn python the hard way, and on chapter 15 I'm suppose to use import argv to assign variables and raw input to gain user input. The script is: from sys import argv script, filename, = argv txt = open(filename) print " Here's your file %r :" % filename print txt.read() print " I'll also ask you to type it again: " file_again = raw_input ("> ") txt_again = open (file_again) print txt_again.read () After running this script I get the error, too many values to unpack. File "ex15.py", line 3, in script , filename = argv Value error: too many values to unpack Just a couple of pointers.

I'm pretty new at python and I've been playing with argv. I wrote this simple program here and getting an error that says : TypeError: %d format: a number is required, not str from sys import argv file_name, num1, num2 = argv int(argv[1]) int(argv[2]) def addfunc(num1, num2): print "This function adds %d and %d" % (num1, num2) return num1 + num2 addsum = addfunc(num1, num2) print "The final sum of addfunc is: " + str(addsum) When I run filename.py 2 2, does argv put 2 2 into strings? If so, how do I convert these into integers? Thanks for your help. sys.argv is indeed a list of strings. Use

When you type "ps aux" the ps command shows command arguments that the program was run with. Some programs change this as a way of indicating status. I've tried changing argv[] fields and it doesn't seem to work. Is there a standard way to set the command line arguments so that they appear when the user types ps? That is, this doesn't work: int main(int argc,char **argv) { argv[0] = "Hi Mom!"; sleep(100); } 09:40 imac3:~$ ./x & [2] 96087 09:40 imac3:~$ ps uxp 96087 USER PID %CPU %MEM VSZ RSS TT STAT STARTED TIME COMMAND yv32 96087 0.0 0.0 2426560 324 s001 S 9:40AM 0:00.00 ./x 09:40 imac3:~$

this is how we use MPI_Init function int main(int argc, char **argv) { MPI_Init(&argc, &argv); … } why does MPI_Init use pointers to argc and argv instead of values of argv? NickTee According to the answer stated here: Passing arguments via command line with MPI Most MPI implementations will remove all the mpirun-related arguments in this function so that, after calling it, you can address command line arguments as though it were a normal (non-mpirun) command execution. i.e. after mpirun -np 10 myapp myparam1 myparam2 argc = 7(?) because of the mpirun parameters (it also seems to add some) and

I have written a small program that takes some input parameters from *argv[] and prints them. In almost all use cases my code works perfectly fine. A problem only arises when I use more than one exclamation mark at the end of the string I want to pass as an argument ... This works: ./program -m "Hello, world!" This does NOT work: ./program -m "Hello, world!!!!" ^^ If I do this, the program output is either twice that string, or the command I entered previous to ./program. However, what I absolutely don't understand: The following, oddly enough, DOES work: ./program -m 'Hello, world!!!!' ^^ The

I'm making a small program in C that deals with a lot of command line arguments, so I decided to use getopt to sort them for me. However, I want two non-option arguments (source and destination files) to be mandatory, so you have to have them as arguments while calling the program, even if there's no flags or other arguments. Here's a simplified version of what I have to handle the arguments with flags: while ((c = getopt(argc, argv, "i:d:btw:h:s:")) != -1) { switch (c) { case 'i': { i = (int)atol(optarg); } case 'd': { d = (int)atol(optarg); } case 'b': buf = 1; break; case 't': time = 1;