argv

I have a C program that reads command line arguments from argv. Is it possible to make a pipe to redirect the contents of a file as command line arguments to my program? Suppose I have a file arguments.dat with this content: 0 0.2 302 0 And I want my program to be called with: ./myprogram 0 0.2 302 0 I tried the following: cat arguments.dat | ./myprogram without success. With most shells, you can insert the contents of a file into a command line with $(<filename) : ./myprogram $(<arguments.dat) If your shell doesn't support that, then one of the older ways will work: ./myprogram $(cat

And does Dart have a getopt library? Tomas Kulich Using Options is no longer an option, use: void main(List<String> args) { print(args); } To get executable, use Platform.executable (Platform comes from dart:io) For parsing arguments passed to main, use this cool package Edit: This is no longer valid, see accepted answer above. See Options . http://api.dartlang.org/dart_io/Options.html List<String> argv = (new Options()).arguments; igor // dart 1.0 import 'dart:io'; void main(List<String> args) { String exec = Platform.executable; List<String> flags = Platform.executableArguments; Uri script =

This is my script def main(argv): if len(sys.argv)>1: for x in sys.argv: build(x) if __name__ == "__main__": main(sys.argv) so from the command line I write python myscript.py commandlineargument I want it to skip myscript.py and simply run commandlineargument through commandlineargument(n) so I understand that my for loop doesn't account for this, but how do I make it do that? Since sys.argv is a list, you can use slicing sys.argv[1:] : def main(argv): for x in argv[1:]: build(x) if __name__ == "__main__": main(sys.argv) But, if you can only have one script parameter, just get it by index:

Is there a way to set argv[0] in a Haskell program (say, one compiled with ghc)? I found the getProgName and withProgName functions in System.Environment, but it doesn't seem to change what ps reports (Ubuntu). import System.Environment main = do name <- getProgName putStrLn $ "Hello, my name is " ++ name withProgName "other" $ do newname <- getProgName putStrLn $ "Name now set to " ++ newname putStrLn "What is your name: " -- allow time to run ps ans <- getLine putStrLn $ "Pleased to meet you, " ++ ans There is no portable way of doing this, but on Linux 2.6.9 and up the process name can be

Is it possible to execute a process whose argc = 0? I need to execute a program but it is extremely important for its argc to be equal to 0. Is there a way to do that? I tried to put 2^32 arguments in the command line so that it appears as if argc = 0 but there is a maximum limit to the number of arguments. You can write a program that calls exec directly; that allows you to specify the command-line arguments (including the program name) and lack thereof. You may use linux system call execve() . int execve(const char *filename, char *const argv[], char *const envp[]); You may pass the filename

I've been all over the documentation and it seems like there's no way to do it, but: Is there a way to use argparse with any list of strings, instead of only with sys.argv? Here's my problem: I have a program which looks something like this: # This file is program1.py import argparse def main(argv): parser = argparse.ArgumentParser() # Do some argument parsing if __name__ == '__main__': main(sys.argv) This works fine when this program is called straight from the command line. However, I have another python script which runs batch versions of this script with different commandline arguments,