arguments

C# publishing an .exe and sending params to it using cmd

你离开我真会死。 提交于 2021-02-04 15:43:27
问题 i am pretty sure this is basic but i just dont success to do this i am trying to create a console application that would do ABC by getting few arguments for start i am trying to run something as simple as that static void Main(string[] args) { foreach (var s in args) { Console.WriteLine(s); } Console.ReadLine(); } when i publish it it comes at as a 'clickonce' project like NAME.application instead of NAME.exe also , when i am trying to go execute it with XYZ parms like trying in same folder

C# publishing an .exe and sending params to it using cmd

社会主义新天地 提交于 2021-02-04 15:42:56
问题 i am pretty sure this is basic but i just dont success to do this i am trying to create a console application that would do ABC by getting few arguments for start i am trying to run something as simple as that static void Main(string[] args) { foreach (var s in args) { Console.WriteLine(s); } Console.ReadLine(); } when i publish it it comes at as a 'clickonce' project like NAME.application instead of NAME.exe also , when i am trying to go execute it with XYZ parms like trying in same folder

querySelector method arguments are put into backtick, why?

≯℡__Kan透↙ 提交于 2021-02-04 14:19:11
问题 I've started Javascript 30. What bothers is like on given example code: const audio = document.querySelector(`audio[data-key="${e.keyCode}"]`); Why are the arguments put into the backticks? I understand how to use double and single quotes and when I can use both. However I don't understand how and when to use backticks. 回答1: The backticks allow you to use the string interpolation syntax ${}. 回答2: You can add expression in string with back-tick. This feature was add on ES6. 回答3: Backticks are

Get all arguments after args[0] discord.js

笑着哭i 提交于 2021-02-02 09:55:54
问题 I was trying to make a mute command, and I was adding a system where you can mute them for a reason. The bot would reply "(Username of user) was muted. Reason: (The reason)". For me args[0] is just mentioning the user that you want to mute, but I can't figure out how to get all after args[0]. I've tried doing something like this message.channel.send('I have muted' + (mutedUser) + 'Reason: ' + args[1++] . But that obviously didn't work - I was kind of guessing - I turned to listing 4 arguments

Get all arguments after args[0] discord.js

会有一股神秘感。 提交于 2021-02-02 09:54:46
问题 I was trying to make a mute command, and I was adding a system where you can mute them for a reason. The bot would reply "(Username of user) was muted. Reason: (The reason)". For me args[0] is just mentioning the user that you want to mute, but I can't figure out how to get all after args[0]. I've tried doing something like this message.channel.send('I have muted' + (mutedUser) + 'Reason: ' + args[1++] . But that obviously didn't work - I was kind of guessing - I turned to listing 4 arguments

Count content inside quotes as one argument

随声附和 提交于 2021-01-29 19:55:22
问题 I'm making a discord bot with node.js's discord.js module, I have a basic arguments detection system that uses the whitespace as the separator and puts the different arguments in an array, here's the important part of my code. (I'm using separate command modules using module.exports ). const args = message.content.slice(prefix.length).split(/ +/); const commandName = args.shift().toLowerCase(); const command = client.commands.get(commandName) || client.commands.find(cmd => cmd.alias && cmd

Why can't I pass an argument to fragment using navigation component when that argument has a default value?

大兔子大兔子 提交于 2021-01-29 19:20:34
问题 I am using navigation component and I don't understand why I get an error passing the argument to the method below if the argument is defined. I am using SafeArgs and I only get this error when I define a default value for this argument. Could someone explain me why this happens and how can I solve it? Here is a part of the code of the navigation graph. <fragment android:id="@+id/sleepTrackerFragment" android:name="com.example.sleeptracker.fragments.sleep_tracker.SleepTrackerFragment" android

Default ofstream class argument in function

流过昼夜 提交于 2021-01-29 07:22:50
问题 I've got function. If user didn't provide ofstream element into this function: bool isPolpierwsza(int, bool = false, ofstream = NULL); than I want to asign "plik" bool isPolpierwsza(int liczba, bool wypisz, ofstream plik) to NULL value. My compiler put error: 2.9.cpp:5:48: error: no viable conversion from 'long' to 'ofstream' (aka 'basic_ofstream') bool isPolpierwsza(int, bool = false, ofstream = NULL); How to setup default value to ofstream to be treated like NULL or "false"? 回答1: You can

Is there a possibility to pass start arguments to setup.py test

半世苍凉 提交于 2021-01-29 03:32:55
问题 I have a problem with the CI of my python project, the project is a python API which communicates with a server. To make it possible, to run builds concurrently I must have a possibility to pass the servers port to the python setup.py test command. For example python setup.py test --port 1337 . Is there any possibility to get this done? At the moment I have a setup.py file and use unittest for testing, but I'm totally free to use another framework like nose. The important thing is to pass the

R- pass argument to ggplot in function

隐身守侯 提交于 2021-01-28 14:27:17
问题 I have a question about how to pass an argument to ggplot if I want to have a 1-x x-axis. The function is being used to specify column name in my data frame. Let's say my data frame looks like x1 x2 x3 x4 0.1 0.2 0.3 0.4 0.3 0.5 0.7 0.9 0.4 0.6 0.8 0.2 And I have a function myfunction<- function(x, y, convert = False){ if (flip) { ggplot(data = mydata, aes(x=1-get(x), y=get(y))) + geom_line() + xlab(x) + ylab(y) } else { ggplot(data = mydata, aes(x=get(x), y=get(y))) + geom_line() + xlab(x) +