and-operator

I would like to know how can I combine multiple boolean coniditions in EL. I have following example and it is not working. <x:someComponent rendered="#{bean.condition1} or #{bean.condition2}"> How can I use "OR" and "AND" logical operators in EL? BalusC The operator has to go inside the EL expression, not outside. You should see the #{...} as one big scope wherein various variables/conditions interact with each other. <x:someComponent rendered="#{bean.condition1 or bean.condition2}"> See also: Our EL wiki page Conditionally displaying JSF components How to conditionally render plain HTML

I have a php code as shown below in which I want to display anything in between two calendar days of the week. The values coming inside $data->{"select_start_day"}; $data->{"start_time"}; $data->{"select_end_day"}; and $data->{"end_time"}; is controlled by the user. PHP Code: if (file_exists('feeds/ptp-ess_landing.json')) { $data = json_decode(file_get_contents('feeds/ptp-ess_landing.json')); } date_default_timezone_set('America/Toronto'); $arradate = strtolower(date('D')); $nowtime = (int)date('His'); $start_day=$data->{"select_start_day"}; $start_time=$data->{"start_time"}; $end_day=$data->{

This question already has an answer here: Difference between “and” and && in Ruby? 7 answers I have a question regarding the and/&&/= keywords in Ruby. The ruby docs say that the precedence for the mentioned keywords is: (1)&&, (2)=, (3)and. I have this snippet of code I wrote: def f(n) n end if a = f(2) and b = f(4) then puts "1) #{a} #{b}" end if a = f(2) && b = f(4) then puts "2) #{a} #{b}" end The output is: 1) 2 4 [Expected] 2) 4 4 [ Why ?] For some reason using the && causes both a and b to evaluate to 4? I don't quite understand the question you are asking. I mean, you have already

Based on this answer Regular Expressions: Is there an AND operator? I tried the following on http://regexpal.com/ but was unable to get it to work. What am missing? Does javascript not support it? Regex: (?=foo)(?=baz) String: foo,bar,baz Mark Byers It is impossible for both (?=foo) and (?=baz) to match at the same time. It would require the next character to be both f and b simultaneously which is impossible. Perhaps you want this instead: (?=.*foo)(?=.*baz) This says that foo must appear anywhere and baz must appear anywhere, not necessarily in that order and possibly overlapping (although