addition | 易学教程

PHP calculation from html form

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问题 I have created a reservations page for a restaurant website, with a form present to book a dinner reservation. It contains a dropdown box which allows the user to select the amount of people who will be dining in their party. It also contains a radio button to allow the user to select if they wish to be seated in the VIP area (Yes/ No). Each person in the party should cost an extra £5 towards their booking fee and if they wish to be seated in the VIP area, they will be charged an additional

big integer addition without carry flag

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问题 In assembly languages, there is usually an instruction that adds two operands and a carry. If you want to implement big integer additions, you simply add the lowest integers without a carry and the next integers with a carry. How would I do that efficiently in C or C++ where I don't have access to the carry flag? It should work on several compilers and architectures, so I cannot simply use inline assembly or such. 回答1: You can use "nails" (a term from GMP): rather than using all 64 bits of a

Binary addition of 2 values represented as strings

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问题 I have two strings: string a = "00001"; /* which is decimal 1 I've converted with next string: string a = Convert.ToString(2, 2).PadLeft(5, '0'); */ string b = "00010"; I want to perform binary addition between the two so the answer will be 00011 ( 3). 回答1: System.Convert should be able to do the work for you int number_one = Convert.ToInt32(a, 2); int number_two = Convert.ToInt32(b, 2); return Convert.ToString(number_one + number_two, 2); (you may have to tune the strings a bit) 回答2: You do

operator+ and move semantics

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问题 How is the proper way to implement move semantics with operator+ ? Similarly to how it works for std::string ? I have attempted the following, however I was hoping there was some more elegant and possibly more correct way to do it: class path { std::vector<std::string> path_; public: path& path::operator+=(const path& other) { path_.insert(std::begin(path_), std::begin(other.path_), std::end(other.path_)); return *this; } path& path::operator+=(path&& other) { path_.insert(std::begin(path_),

What happens if you remove the space between the + and ++ operators?

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问题 EDIT 1 DISCLAIMER: I know that +++ is not really an operator but the + and ++ operators without a space. I also know that there's no reason to use this; this question is just out of curiosity. So, I'm interested to see if the space between + and ++var is required in Java. Here is my test code: int i = 0; System.out.println(i); i = i +++i; System.out.println(i); This prints out: 0 1 which works as I would expect, just as if there were a space between the first and second + . Then, I tried it

Bitwise saturated addition in C (HW)

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问题 I'm working on an assignment and I can't figure out how to implement this. I have to make a function sadd(int x, int y) that returns the numbers added together unless it overflows (then just return the max possible int). I've been able to come up with some solutions involving casting and conditional statements, but those aren't allowed in the solution. Only the operators ~ ! ^ + << >> & and | . 回答1: For addition of signed numbers, overflow has happened if you add two numbers of the same sign

Why is number + string a string in javascript?

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问题 Sort of trying out some quirks in javascript: First I did console.log("5" + 1); This prints 51, this is normal right, both number and string have a + operator, but since string is the first variable it will convert 1 to a string. Now when I did this: console.log(1 + "5") I expected output to be 6, as I thought it would convert string to a number. However, the magic output was 15. Could anyone more experienced in javascript brighten this up for me? 回答1: Quoting ECMAScript spec The Addition

Sum of previous two numbers entered

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问题 I am working a simple beginner loop program, where i am trying to get an integer input from the user and calculate the sum. I have a simple menu in which the user can select one of for options, the first being inputting a number and second showing the sum of the last two numbers entered. So i need the program to add the previous two entered numbers together. so if the user selects option 1, they can enter a number and then be returned to the menu where they have to select option 1 again to

Calculate exponents via addition only

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问题 We're writing a very simple program to execute on a processor we've built for a class. It doesn't have the capability to multiply or divide. We do however, had support for addition, subtraction, and, or, and branching for loop control (like branch on equal if you are familiar with MIPS). We were thinking a neat program to run on it would be some sort of x^n program. Of course, those numbers would have to be hardcoded, but given the limitations of our processor, is it realistic? Is there an

PHP calculation from html form

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I have created a reservations page for a restaurant website, with a form present to book a dinner reservation. It contains a dropdown box which allows the user to select the amount of people who will be dining in their party. It also contains a radio button to allow the user to select if they wish to be seated in the VIP area (Yes/ No). Each person in the party should cost an extra £5 towards their booking fee and if they wish to be seated in the VIP area, they will be charged an additional £5. Once the form validation is successful, the user will be sent to a confirmation page, where the