addition

问题 Why is adding a sparse and a full matrix slower than adding two full matrices? The following code demonstrates consistent superior performance for hFullAddFull . I_FULL = 600; J_FULL = 10000; FULL_COUNT = I_FULL*J_FULL; NON_ZERO_ELEMENT_COUNT = 1000; nonZeroIdxs = randsample(FULL_COUNT, NON_ZERO_ELEMENT_COUNT); mat_Sp = spalloc(I_FULL, J_FULL, NON_ZERO_ELEMENT_COUNT); mat_Sp(nonZeroIdxs) = 0.5; mat_Full = full(mat_Sp); otherMat_Full = rand(I_FULL, J_FULL); hFullAddSp = @()otherMat_Full+mat_Sp

问题 This question already has answers here : Dictionary error: Ambiguous reference to member '+' [duplicate] (4 answers) Closed 2 years ago . teaching myself swift I am trying to understand how dictionaries work. Using playground. I have made a simple dictionary called "menu" that has a list of items with their name as keys and their price as values. Like so: let menu = ["crisps": 2, "oranges": 3, "chicken": 8, "meat": 12] Then, I try to add the values of those items like so: let costOfMeal =

问题 I would like to add up the upper part diagonals of a matrix starting from the middle, with increment in column until (1,n), n being the last column and save each sum of every diagonal. My code only add the middle diagonal, how can I loop through the matrix to get the sum of the diagonals A <- matrix(c(2, 4, 3, 1, 5, 7, 1, 2, 3, 2, 3, 4, 1, 5, 6, 0), # the data elements nrow = 4, # number of rows ncol = 4, # number of columns byrow = TRUE) # fill matrix by rows sum <- 0 print(A) for (a in 1){

问题 I need to write a Prolog predicate which calculate the sum of 2 binary numbers represented in list. The lists are already reversed, for example ([0,1] base 2) = (2 base 10). It should work with mode binary_plus(+,+,-), for example ?- binary_plus([1,1],[1],X). X = [0,0,1]. and with mode binary_plus(-,-,+), for example ?- binary_plus(X,X,[0,1]). X = [1]. Im not allowed using cut sign,findall,negation,or if-then-else. Here is my code: is_binary([]). is_binary([X]):- X is 1. is_binary([X|Xs]):-

问题 Is it possible to craft a query that adds values within two tables: For example, say you have two tables id value -- ----- a 1 c 2 d 3 f 4 g 5 and id value -- ----- a 1 b 2 c 3 d 4 e 5 Then when you 'add' the two tables you would get the result where the id's match. So, a=1+1=2, and simply the same result where they don't. So the query would return: id value -- ----- a 2 b 2 c 5 d 7 e 5 f 4 g 5 回答1: maybe something like select coalesce(t1.id, t2.id) as id, (coalesce(t1.value, 0) + coalesce(t2

问题 I am trying to add and subtract dollars and cents but I am having trouble with going over 100 cents and under 0 cents. My code works fine for adding anything until I need to convert 100 cents into a dollar. I'm having trouble putting my words into code, but I understand what needs to be done to convert cents into a dollar. FYI this is for a class so that is why I have code for static method addition/subtraction and class method addition/subtraction My code: package moneyapp; public class

问题 Suppose that I have two arrays: $v_4 = array(array(1,2,3),array(4,5,6)); $v_5 = array(array(7,8,9),array(10,11,12)); How should I construct an addition function to add across these arrays so as to get: $new_array = array(array(8,10,12),array(14,16,18)); I know I need to utilise array_map somehow, but I am unsure how to proceed in the multidimensional case. 回答1: You can use $new = array(); foreach(array_map(null, $v_4, $v_5) as $var) { $data = call_user_func_array("array_map", array_merge

问题 When I'm directly adding an integer value(i.e: 1,2,3,etc) with another integer variable let arr:Array = ["One","Two"] var valueT:Int64 = 0 value = arr.count + 1 //in this line I get the following warning: '+' is deprecated: Mixed-type addition is deprecated. Please use explicit type conversion. I fixed it the warning with this : value = Int64(value + 1) Though it is fixed but I wanna know why its called Mixed-type addition as I didn't use ++ . Also is there a better way to fix the warning in

问题 I know that the unary operator ++ adds one to a number. However, I find that if I do it on an int pointer, it increments by 4 (the sizeof an int on my system). Why does it do this? For example, the following code: int main(void) { int *a = malloc(5 * sizeof(int)); a[0] = 42; a[1] = 42; a[2] = 42; a[3] = 42; a[4] = 42; printf("%p\n", a); printf("%p\n", ++a); printf("%p\n", ++a); return 0; } will return three numbers with a difference of 4 between each. 回答1: It's just the way C is - the full

问题 I have the following code. I want to add two input fields together and output it to the page. I get as far as being able to output what is type in the input field however I can't figure how to add the two fields together and output it. I have it at http://jsfiddle.net/erick/9Dj3j/3/ Jquery $(function() { var output_element = $('#output_ele'); var output_element1 = $('#output_ele1'); $('#the_input_id').keyup(function() { var their_input = $(this).val(); var firstInput = output_element.text