2d

问题 I have two 2D arrays, I want to compare them using JavaScript, ignore the matches and if there are mismatches to return the entire row into a new array. var array1 = [ ['52a1fd0296fc','DEF'], ['52a1fd0296fc','DEF'], ['52a1fd0296fc','DEF'], ['52a1fd0296fc','DEF'], [null,'ABC'], ['6f93cfa0106f','xxx'], ]; var array2 = [ ['52a1fd0296fc','ABC'], ['6f93cfa0106f','xxx'], ['52a1fd0296fc','ABC'], ['52a1fd0296fc','ABC'], ['52a1fd0296fc','DEF'], ['52a1fd0296fcasd','DEF'], ]; I want to take this output,

问题 I see plenty of answers to this riddle on here, but every time I try and implement the answers, they don't seem to work. I wanted to reply to some of the answers, but couldn't. Perhaps it's because of my 'reputation' level? Anyway, it's a simple coordinates problem for a game. Simple for most, but not for me. (suck at math.. hardcore) I've got a spaceship in the middle of the screen. It does not move apart from rotation (user.fAngle). It does have velocity (user.dVelocity) that is used purely

问题 I have two vectors and i want to know where these vectors will intersect independent from direction or length. So lets just say i would draw an infinite line in either direction and i want to know where those two lines will intersect and get the coordinates. See image below for clarification: So i want to know the coordinates of the pink X. But i can only find formulas for calculating the intersection point of two lines with an stard and end point which i dont have :( So i am looking for some

问题 I am new to using CGAL, and I was wondering if CGAL supports 2D Delaunay triangulation of 3D points using an arbitrary plane. The example on CGAL's documentation lists only Projection_traits_xy_3<R> , Projection_traits_yz_3<R> , and Projection_traits_xz_3<R> , in other words, projection on the xy plane, the yz plane and the xz plane. Is there any way I can define an arbitrary projection plane instead of using the xy, yz and xz planes? thanks, 回答1: There is a template < class Kernel > class

问题 EDIT: I updated the program with the answer and it works great! I am making a program (feel free to try it out) that lets users draw polygons which it then triangulates. They can click to add vertices and hit enter to triangulate. Anyways, the algorithm works fine as long as I tell it if the points were drawn in a clockwise or counterclockwise fashion (right now I have it set only to work with clockwise polygons). I have been trying to figure this out for days, but have no idea how to

问题 I'm trying to draw a triangle using an OpenGL fragment shader. I succeeded in drawing a circle but I have a problem with handling the equation/logic or the code to draw a triangle. draw_triangle(vec2 v1 , vec2 v2, vec2 v3) Here is the fragment shader: #version 330 core out vec4 frag_color; void draw_circle(vec2 shift_val, int radius,int color) { vec2 res = vec2(1280,720); vec2 norm_cord = gl_FragCoord.xy; float dist = length(norm_cord - (res*shift_val)); if( dist < radius ) { if( color ==1 )

问题 I'm trying to draw a triangle using an OpenGL fragment shader. I succeeded in drawing a circle but I have a problem with handling the equation/logic or the code to draw a triangle. draw_triangle(vec2 v1 , vec2 v2, vec2 v3) Here is the fragment shader: #version 330 core out vec4 frag_color; void draw_circle(vec2 shift_val, int radius,int color) { vec2 res = vec2(1280,720); vec2 norm_cord = gl_FragCoord.xy; float dist = length(norm_cord - (res*shift_val)); if( dist < radius ) { if( color ==1 )

问题 I'm trying to draw a triangle using an OpenGL fragment shader. I succeeded in drawing a circle but I have a problem with handling the equation/logic or the code to draw a triangle. draw_triangle(vec2 v1 , vec2 v2, vec2 v3) Here is the fragment shader: #version 330 core out vec4 frag_color; void draw_circle(vec2 shift_val, int radius,int color) { vec2 res = vec2(1280,720); vec2 norm_cord = gl_FragCoord.xy; float dist = length(norm_cord - (res*shift_val)); if( dist < radius ) { if( color ==1 )

问题 I'm trying to draw a triangle using an OpenGL fragment shader. I succeeded in drawing a circle but I have a problem with handling the equation/logic or the code to draw a triangle. draw_triangle(vec2 v1 , vec2 v2, vec2 v3) Here is the fragment shader: #version 330 core out vec4 frag_color; void draw_circle(vec2 shift_val, int radius,int color) { vec2 res = vec2(1280,720); vec2 norm_cord = gl_FragCoord.xy; float dist = length(norm_cord - (res*shift_val)); if( dist < radius ) { if( color ==1 )

问题 I'm trying to draw a triangle using an OpenGL fragment shader. I succeeded in drawing a circle but I have a problem with handling the equation/logic or the code to draw a triangle. draw_triangle(vec2 v1 , vec2 v2, vec2 v3) Here is the fragment shader: #version 330 core out vec4 frag_color; void draw_circle(vec2 shift_val, int radius,int color) { vec2 res = vec2(1280,720); vec2 norm_cord = gl_FragCoord.xy; float dist = length(norm_cord - (res*shift_val)); if( dist < radius ) { if( color ==1 )