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问题 I have a star image in action bar. When I click on it, then the image should change to ON star. This is working fine. But how to know whether image is at ON state or OFF state.I want something that, if the image is at OFF mode and user taps on ON star, then it should set to ON star image. Initially, the image is set to OFF mode. So for this, I've wrote give line to turn on as user tap on it : v.setBackgroundResource(android.R.drawable.star_big_on); Guys pls suggest me for OFF mode if star

问题 I have a c program that executes another process (bash script) with fork and execlp. When I want to kill this process it moves to a zombiee state. Why is this?? Create a process: switch (PID_BackUp= fork()) { case -1: perror("fork"); printf("An error has occurred launching backup.sh script!\n"); break; case 0: execlp("/usr/local/bin/backup.sh", "/usr/local/bin/backup.sh", NULL, NULL, NULL); break; default: printf("backup.sh script launched correctly! PID: %d\n", PID_BackUp); break; } Kill a

问题 for example I have a schema const listSchema=new mongoose.Schema({ name:String, items:Array }); const List=mongoose.model("List",listSchema); and I made a document const list=New List({ name: "list1", items:[item1, item2,item3] }); and then later I wanted to add a new item called item 4 so I used List.findOne({name:list1},function(err,foundList){ foundList.items.push(item4); foundList.save(); I know it might be a stupid question but it's confusing me. When I use .push I essentially added a

问题 In view on click of button am using location.href to pass on to controller. How can i pass the localstorage value in order to use it as a php variable In view: echo Html::button('Proceed', [ 'onclick' => " var dataVal = localStorage.getItem('Customers'); if(dataVal.length > 0) { location.href = '" . Yii::$app->urlManager->createUrl(['customers/orders']) . "'; }else{ alert('Please add some items to order!') return false; }",]); 回答1: While this is generally not recommended practice, it is

问题 From C++ Primer 5th edition By Stanley Lippman et al(19.5): A nested class can have the same kinds of members as a nonnested class. Just like any other class, a nested class controls access to its own members using access specifiers. The enclosing class has no special access to the members of a nested class, and the nested class has no special access to members of its enclosing class . Is there any truth to the bolded part? I could find no mention of the nested class being restricted access

问题 I have a dataframe with table style that I created : tableyy = final.style.set_table_attributes('border="" class = "dataframe table table-hover table-bordered"').set_precision(10).render() I have go through this Coloring Cells in Pandas , Conditionally change background color of specific cells, Conditionally format Python pandas cell, and Colour cells in pandas dataframe, I still not able to set a cell with color not the whole dataframe without any condition. Anyone have any ideas, I try this

问题 I created a route for navigating from one page to another, in the following way class task extends StatelessWidget{ @override Widget build(BuildContext context) { return MaterialApp( title: 'Task', home: new task(), routes: <String, WidgetBuilder>{ "/Completed": (BuildContext context) => new Completed() } ); } } class taskScreen extends StatefulWidget{ @override taskState createState() => new taskState(); } class taskState extends State<taskScreen> { @override Widget build(BuildContext

问题 When I try to play .mp3 file by using AudioClip with JavaFX 8u40 it says: com.sun.media.jfxmedia.MediaException: Could not create player! which means Java installation do not see my mp3 codec - but all other OS programs see it, even programs on Qt can play mp3. This error happened after upgrading to Ubuntu 14.10 (On 14.04 all was fine, the same programs play all the media formats) libav... all packages are all installed. 来源： https://stackoverflow.com/questions/27195853/javafx-mp3-playback

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . Improve this question Given a raw string input 1600 Divisadero St San Francisco, CA 94115 b/t Post St & Sutter St Lower Pacific Heights I want to extract City: San Francisco state: California or CA Country: USA I'll be parsing millions of addresses and using a Paid API is not feasible

问题 I have an external library in the project: The project uses methods from this library For me, the classes in this library are read-only I need to change the method logic from an external library a little bit What and how should I do? Maybe I should create new class in project with the same logic? (+ my changes) Maybe other solutions? 回答1: If you use Kotlin you could use Extension Function to extend class functionalities with no need to extend it. You use Java you could extend the classes and