Libev, How to pass arguments to relevant callbacks

匿名 (未验证) 提交于 2019-12-03 08:33:39

问题:

I'm trapped in a situation of argument passing in libev.

Usually, libev receives packages in a function like *receive_callback*, that's OK, but in practice, we need to dispatch a relative *write_callback* to deal with specific jobs according to the received package. For example:

S_RECV_MSG* pstRecvMsg = (S_RECV_MSG*) recv_buff; switch(pstRecvMsg->wMsgType) {     case 1:          ev_io_init(w, write_callback1, w->fd, EV_WRITE);         break;     case 2:         ev_io_init(w, write_callback2, w->fd, EV_WRITE);         break;     case 3:         // ....... }

My question is, if the write_callbackX also has to read the specific content in the recv_buff, how can we pass the recv_buff argument to the callbackX? Must we bear the burden and ugliness of global variables here?

回答1:

The author answered it himself, but in a comment. Since this shows up as unanswered, I am posting his answer in the "answer" section and closing the loop. Not sure if there is a better way... feel free to fix this.

Question author says:

Sorry, I think I got the answer now, and feel deeply ashamed at my carelessness of reading documentation:

struct my_io{    ev_io io;    int otherfd;    void *somedata;    struct whatever *mostinteresting; }; // ... struct my_io w; ev_io_init (&w.io, my_cb, fd, EV_READ);

And then we use the my_io like this:

static void my_cb (struct ev_loop *loop, ev_io *w_, int revents) {    struct my_io *w = (struct my_io *)w_;    //... }


回答2:

Yes it's explained in libev document, and there is another way. Each watcher has a void *data member that you can read or modify, and libev will completely ignore it, so you can pass the argument like this:

w->data = (void *)recv_buff; ... static void my_cb (struct ev_loop *loop, ev_io *w_, int revents) {     S_RECV_MSG *recv_buff = (S_RECV_MSG*)w_->data;     ... }

see libev document.



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