问题
In python I can pass a dict whose keys match parameters' names with the **
(double-splat) operator:
def foo(a, b):
print (a - b)
args = {'b': 7, 'a': 10}
foo(**args) # prints 3
How to do the same in ES6? This doesn't work:
function foo(a, b) {
console.log(a - b)
}
args = {b: 7, a: 10}
foo(...args)
NB: I'm looking for a solution that wouldn't involve changing the signature of foo
because I want it to be used either way (with and without destructuring). So the following should work:
foo(<magic>args);
foo(123, 456);
Bonus question: why is the error message "undefined is not a function"? What exactly is undefined here?
(As answered by @Nina Scholz in the comments, this is because ...
requires its argument to have Symbol.iterator
, which is not defined for objects).
回答1:
How to do the same in ES6?
There are no named arguments in JS, only positional ones. So the answer is: you can not.
What you can do is either emulate named arguments via object passing, as @Andy suggested.
function foo({ a, b }) {
console.log(a - b);
}
let args = { b: 7, a: 10 };
foo(args);
Or you could make args
to be an array, so you can destruct it into positional arguments.
function foo(a, b) {
console.log(a - b);
}
let args = [10, 7];
foo(...args);
Okay-okay, just for the sake of the argument: it is possible to write a function that will extract parameters of foo
and yield properties of args
in required order.
function * yolo(args, fn) {
const names = fn.toString().match(/\(.+\)/)[0]
.slice(1, -1).split(',')
.map(x => x.trim());
while (names.length) {
yield args[names.shift()];
}
}
function foo(a, b) {
console.log(a - b);
}
const args = { b: 7, a: 10 };
foo(...yolo(args, foo));
I would not dare to use it in production though.
回答2:
You need to wrap your args
in curly braces, and again in the argument list for the function.
function foo({a, b}) {
console.log(a - b)
}
let args = {b: 7, a: 10}
foo({...args})
来源:https://stackoverflow.com/questions/45735576/parameter-destructuring-equivalent-of-pythons-double-splat