Are the k-fold cross-validation scores from scikit-learn's `cross_val_score` and `GridsearchCV` biased if we include transformers in the pipeline?

无人久伴 提交于 2019-12-01 18:44:52

问题


Data pre-processers such as StandardScaler should be used to fit_transform the train set and only transform (not fit) the test set. I expect the same fit/transform process applies to cross-validation for tuning the model. However, I found cross_val_score and GridSearchCV fit_transform the entire train set with the preprocessor (rather than fit_transform the inner_train set, and transform the inner_validation set). I believe this artificially removes the variance from the inner_validation set which makes the cv score (the metric used to select the best model by GridSearch) biased. Is this a concern or did I actually miss anything?

To demonstrate the above issue, I tried the following three simple test cases with the Breast Cancer Wisconsin (Diagnostic) Data Set from Kaggle.

  1. I intentionally fit and transform the entire X with StandardScaler()
X_sc = StandardScaler().fit_transform(X)
lr = LogisticRegression(penalty='l2', random_state=42)
cross_val_score(lr, X_sc, y, cv=5)
  1. I include SC and LR in the Pipeline and run cross_val_score
pipe = Pipeline([
    ('sc', StandardScaler()),
    ('lr', LogisticRegression(penalty='l2', random_state=42))
])
cross_val_score(pipe, X, y, cv=5)
  1. Same as 2 but with GridSearchCV
pipe = Pipeline([
    ('sc', StandardScaler()),
    ('lr', LogisticRegression(random_state=42))
])
params = {
    'lr__penalty': ['l2']
}
gs=GridSearchCV(pipe,
param_grid=params, cv=5).fit(X, y)
gs.cv_results_

They all produce the same validation scores. [0.9826087 , 0.97391304, 0.97345133, 0.97345133, 0.99115044]


回答1:


No, sklearn doesn't do fit_transform with entire dataset.

To check this, I subclassed StandardScaler to print the size of the dataset sent to it.

class StScaler(StandardScaler):
    def fit_transform(self,X,y=None):
        print(len(X))
        return super().fit_transform(X,y)

If you now replace StandardScaler in your code, you'll see dataset size passed in first case is actually bigger.

But why does the accuracy remain exactly same? I think this is because LogisticRegression is not very sensitive to feature scale. If we instead use a classifier that is very sensitive to scale, like KNeighborsClassifier for example, you'll find accuracy between two cases start to vary.

X,y = load_breast_cancer(return_X_y=True)
X_sc = StScaler().fit_transform(X)
lr = KNeighborsClassifier(n_neighbors=1)
cross_val_score(lr, X_sc,y, cv=5)

Outputs:

569
[0.94782609 0.96521739 0.97345133 0.92920354 0.9380531 ]

And the 2nd case,

pipe = Pipeline([
    ('sc', StScaler()),
    ('lr', KNeighborsClassifier(n_neighbors=1))
])
print(cross_val_score(pipe, X, y, cv=5))

Outputs:

454
454
456
456
456
[0.95652174 0.97391304 0.97345133 0.92920354 0.9380531 ]

Not big change accuracy-wise, but change nonetheless.




回答2:


Learning the parameters of a prediction function and testing it on the same data is a methodological mistake: a model that would just repeat the labels of the samples that it has just seen would have a perfect score but would fail to predict anything useful on yet-unseen data. This situation is called overfitting. To avoid it, it is common practice when performing a (supervised) machine learning experiment to hold out part of the available data as a test set X_test, y_test

A solution to this problem is a procedure called cross-validation (CV for short). A test set should still be held out for final evaluation, but the validation set is no longer needed when doing CV. In the basic approach, called k-fold CV, the training set is split into k smaller sets (other approaches are described below, but generally follow the same principles). The following procedure is followed for each of the k “folds”:

A model is trained using of the folds as training data; the resulting model is validated on the remaining part of the data (i.e., it is used as a test set to compute a performance measure such as accuracy). The performance measure reported by k-fold cross-validation is then the average of the values computed in the loop. This approach can be computationally expensive, but does not waste too much data (as is the case when fixing an arbitrary validation set), which is a major advantage in problems such as inverse inference where the number of samples is very small.

More over if your model is already biased from starting we have to make it balance by SMOTE /Oversampling of Less Target Variable/Under-sampling of High target variable.



来源:https://stackoverflow.com/questions/57651455/are-the-k-fold-cross-validation-scores-from-scikit-learns-cross-val-score-and

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