I encountered a few minor issues while working with PyQt4 under Python 2.7
I'm writing a little project where there are some QDialogs opening each other. So there is one Dialog I open and instantly open another Dialog to check something and when there is an error checking, i want the whole dialog to close. it looks like this:
class MyDialog(QtGui.QDialog):
def __init__(self):
## should get me a 10 digit number input
text, ok = QtGui.QInputDialog.getText(self, u'Enter check')
if ok:
## if clicked ok, assign tID
tID = text
else:
## else close
self.close()
try:
## checker is a plausibilty check for the input
## checks, if tID is a number and 10 digits long
## and throws an IntegrityWarning if one of these conditions
## is not met
tID = self.checker.checkID(tID)
except IntegrityWarning as e:
## on exception show error dialog
errDialog = QtGui.QMessageBox()
errDialog.setWindowTitle(u'Fehler')
errDialog.setText(e.getWarning())
ok = errDialog.exec_()
if ok != True:
## close the whole dialog if user cancels
self.close()
self.tAccount = self.tControl.getAccount(tID)
So this is basically what I do and it works just fine except that I get the Errormessage of using tID before assignment. My Programm works just fine after that but I wonder where the error comes from. What strikes me as curious though, is the fact that even if i put the last assignment of tAccount into a try-except: pass statement, the error is thrown to the console, and not passed, as it should be obviously. So my guess was that i can't simply terminate the programm in the __init__()
routine. I tried a return statement instead of the close() statement and destroyed the QDialog in the caller function which is in the MainWindow. This made the Dialog appear and stay empty, as it as modal, i had to close it to resume in the MainWindow.
Can someone please tell me why the Dialog __init__()
resumes after being closed?
This is normal behavior of Python. self.close()
is not a return statement, so it will not exit from __init__
.
Furthermore, __init__
does not actually show the dialog on screen, so writing self.close()
in __init__
is pointless. I'd suggest restructuring your code so this application logic is outside of the __init__
and will decide whether to initialize and show a MyDialog
based on the results from QInputDialog
and checker
来源:https://stackoverflow.com/questions/31351116/pyqt-self-close-in-init