java.lang.IndexOutOfBoundsException: Index: 0, Size: 0 exception [duplicate]

别说谁变了你拦得住时间么 提交于 2019-12-01 08:15:44

The problem is that you are using set method to update element at index 0

set(index,value) method needs an element to present at that index

but you haven't added any element at that position in medium arraylist before that .

So you need to first add an element at index 0 thereafter only you can update it with set method

You need to use

mediums.add(adDistribution.get(0));

rather than mediums.set(0, adDistribution.get(0)); etc.

ArrayList.set(int, Object) requires there to be an element to replace:

Replaces the element at the specified position in this list with the specified element.

Throws: IndexOutOfBoundsException - if the index is out of range (index < 0 || index >= size())

In a new list, size() == 0, so set(0, something) fails.

EDIT: I just removed the unnecessary if statements and simplified them to make your code more readable.
Then I have replaced the set functions with the add function, because the set only can set existing elements.

EDIT2: Based on Andy Turner's answer, I modified my code. Thank you for the suggestions!

After these modifications, the code should look like this (add/remove/modify it for your needs):

public Collection<AdDistribution> getAdDistribution(byte srch, byte cont) throws IndexOutOfBoundsException {

    List<AdDistribution> mediums = new ArrayList<>();

    if( ( srch == 0 && cont == 0 ) || srch == 1 ) {
        mediums.add(AdDistribution.SEARCH);
    }

    if( cont == 1 ) {
        mediums.add(AdDistribution.CONTENT);
    }

    return mediums;
}
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