fitting a linear surface with numpy least squares

问题

So I want to solve the equation z= a + b*y +c*x,. getting a,b,c. ie: making a (plane) surface fit to a load of scatter points in 3D space.

But I can't seem to find anything! I thought there would be a simple module for such a simple problem.

I have tried, where x,y,z are arrays;

ys=zip(x,y)
(coeffs, residuals, rank, sing_vals) = np.linalg.lstsq(ys,z)

am I right in thinking coeffs = b,c? Or am I going completely in the wrong direction. I just can't seem to find anything else that will work in 3d...

回答1:

I think you're on the right track. You could still try following the example of the scipy.linalg documentation, in particular the Solving least-squares...` section

A = np.column_stack((np.ones(x.size), x, y))
c, resid,rank,sigma = np.linalg.lstsq(A,zi)

(we added a column of 1 for the constant).

回答2:

The constants a, b, and c are the unknowns you need to solve for.

If you substitute your N (x, y, z) points into the equation, you'll have N equations for 3 unknowns. You can write that as a matrix:

[x1 y1 1]{ a }   { z1 }
[x2 y2 1]{ b }   { z2 }
[x3 y3 1]{ c } = { z3 }
    ...
[xn yn 1]        { zn }

Or

Ac = z

where A is an Nx3 matrix, c is a 3x1 vector and z is a 3xN vector.

If you premultiply both sides by the transpose of A, you'll have an equation with a 3x3 matrix that you can solve for the coefficients you want.

Use LU decomposition and forward-back substitution.

来源：https://stackoverflow.com/questions/12617985/fitting-a-linear-surface-with-numpy-least-squares