This question already has an answer here:
I understand that this error can not be overcome.
But what I would like to do is that when I encounter a page that can't be embed instead the page simply loads as a pop up. What is currently happening is that I am being redirected to the page.
I see the following error in chrome for pages that are unable to be embedded.
Refused to display 'http://www.nokia.com/us-en/' in a frame because it set 'X-Frame-Options' to 'SAMEORIGIN'
Jonathon Klem
Here is a link to a similar answer that provides a PHP script to check the headers: Detect X-Frame-Options
You can modify it so that it takes a GET variable as such:
$error=false;
$urlhere=$_GET["url"];
$ch = curl_init();
$options = array(
CURLOPT_URL => $urlhere,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HEADER => true,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_ENCODING => "",
CURLOPT_AUTOREFERER => true,
CURLOPT_CONNECTTIMEOUT => 120,
CURLOPT_TIMEOUT => 120,
CURLOPT_MAXREDIRS => 10,
);
curl_setopt_array($ch, $options);
$response = curl_exec($ch);
$httpCode = curl_getinfo($ch);
$headers=substr($response, 0, $httpCode['header_size']);
if(strpos($headers, 'X-Frame-Options: deny')>-1||strpos($headers, 'X-Frame-Options: SAMEORIGIN')>-1) {
$error=true;
}
$httpcode= curl_getinfo($ch, CURLINFO_HTTP_CODE);
curl_close($ch);
echo json_encode(array('httpcode'=>$httpcode, 'error'=>$error));
Then use an ajax request to test each url
$.getJSON("/path/to/script.php?url="+url_variable, function (data) {
if (data.error) {
// code to display pop-up
} else {
// code to display iframe
}
});
来源:https://stackoverflow.com/questions/16323151/catching-display-forbidden-by-x-frame-options