问题
The following code snippet is meant to try and extract an integer from a string using a stringstream object and detect whether integer extraction was successful or not. The stringstream class inherits the >> operator to return a reference to an istream instance. How does failed integer extraction lead to myStream being equal to 0 while its str member is still strInput?
stringstream myStream(strInput);
if (myStream >> num){//successfull integer extraction}
else{//unsuccessfull integer extraction
cout<<myStream<<endl;
cout<<myStream.str().c_str()<<endl;}
回答1:
There is an operator bool() or operator void*() for stream, which returns (something like) !fail() - or in case of void * a NULL when it failed. So, if the stream hasn't failed, it's fine. The operator >> returns a reference to the stream object, so the compiler says "Hmm, can't compare a stream object to truth, let's see if we can make a bool, or void * from it, yes we can, so let's use that.
回答2:
The answer is in the operator that converts std::ios to void* (replaced with an operator to convert basic_ios to a bool in C++11):
A stream object derived from ios can be casted to a pointer. This pointer is a null pointer if either one of the error flags (failbit or badbit) is set, otherwise it is a non-zero pointer.
This operator gets called when your stream is used in an if, while, or for condition. There is also a unary ! operator for the cases when you need to write
if (!(myStream >> num)) {
...
}
来源：https://stackoverflow.com/questions/14804046/using-stringstream-operator-in-if-statement