How to compute an exponent in matlab without getting inf?

女生的网名这么多〃 提交于 2019-11-30 22:15:06

As Daniel has already pointed out, it's too big a number to be even outputted by MATLAB itself. This number is obtained with realmax for different datatypes. As an alternative to represent/use such huge numbers, you can use the corresponding mantissa and exponent with base-10 representation instead, which is the usual MATLAB representation. The function to get those two is listed here -

function [mantissa, base10_exponent] = base10_mantissa_exponent(base,exponent)

act_exp = exponent*log10(abs(base));
base10_exponent = floor(act_exp);
mantissa = power(10,act_exp - base10_exponent);

if rem(exponent,2)==1 && sign(base)==-1
    mantissa = -mantissa;
end

return;

Few example runs and comparisons with actual MATLAB runs for validation are listed next.

Ex #1

base = -125.343;
exponent = 101;
usual_approach = base^exponent
[mantissa, base10_exponent] = base10_mantissa_exponent(base,exponent)

Output -

usual_approach =
 -8.0930e+211
mantissa =
   -8.0930
base10_exponent =
   211

Ex #2 (problem discussed in the question)

base = 100;
exponent = 1000;

Output -

usual_approach =
   Inf
mantissa =
     1
base10_exponent =
        2000

Working with 64bit floating point arithmetic, 100^1000 is inf because it is larger than the largest possible value. If the symbolic math toolbox is available, use vpa or sym to work with large numbers:

sym('100^1000')

or

vpa('100^1000')

To deal with large numbers there is also the class High Precision Float, with which the result can be achieved by writing

a = hpf(100);
b = hpf(1000);
c = a^b;

which gives c = 1.e2000. A call to struct(c) provides informations on how the number is internally stored.

struct(c)

ans = 

NumberOfDigits: [64 4]
   DecimalBase: 4
          Base: 10000
       Numeric: 0
          Sign: 1
      Exponent: 2001
        Migits: [1000 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
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