Select columns by name rather than letter in Google Query Language (GQL) with Google Spreadsheets?

此生再无相见时 提交于 2019-11-30 19:49:34

This is currently not possible. The GQL documentation states[1] "Columns are referenced by the identifiers (not by labels). For example, in a Google Spreadsheet, column identifiers are the one or two character column letter (A, B, C, ...)."

If you want to do this in a spreadsheet it is possible with the following formula to convert a column header name into a letter (some tweaking might be required +1 (might be +2)). It also relies on column headers being unique and not containing commas

=REGEXEXTRACT(ADDRESS(1,COUNTA(SPLIT(LEFT(JOIN(",",TRANSPOSE(1:1)),FIND("your_column_name",JOIN(",",TRANSPOSE(1:1)))),","))+1,4);"[a-zA-Z]+")

[1] https://developers.google.com/chart/interactive/docs/querylanguage#Select

A little simpler:

SELECT "&SUBSTITUTE(ADDRESS(1,MATCH("student",Sheet1!A1:B1,0),4),1,"")&", COUNT("&SUBSTITUTE(ADDRESS(1,MATCH("detention",Sheet1!A1:B1,0),4),1,"")&") GROUP BY "&SUBSTITUTE(ADDRESS(1,MATCH("student",Sheet1!A1:B1,0),4),1,"")

I found that when you use IMPORTRANGE function on external ranges it converts from a letter to a column number, and will help you in this matter.

I've wanted to select a column based on its field name, but the problem for me was that the column to look at was likely to change in the future. So what I did was use the MATCH function to identify the column, so it looks something like

=QUERY(IMPORTRANGE("spreadsheet url","NamedRange"),"SELECT Col"&MATCH("FieldName",FieldNameRowAddress/RangeName,FALSE)")

The funny thing is you have to allow permission to access itself.

I've named my ranges that I'm importing to make it even more future proof.

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