\(A \cup B\) , \(A\)交\(B\)
\(|A \cup B \cup C|=(A+B+C)-(A \cap B+B \cap C+A \cap C)\)
\(|A \cup B \cup C \cup D|=......\)
\(|A_1 \cup A_2...A_n|=\sum_{} A_i - \sum_{} A_i \cap A_j+ \sum_{i<j<k}A_i \cap A_j \cap A_k\)...
来源:https://www.cnblogs.com/defense/p/11568462.html