How to query values from xml nodes?

Deadly 提交于 2019-11-26 09:45:36

问题


i have a table that contains an XML column:

CREATE TABLE Batches( 
   BatchID int,
   RawXml xml 
)

The xml contains items such as:

<GrobReportXmlFileXmlFile>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>
   <GrobReport>
       <ReportHeader>
          <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
          <OrganizationNumber>4</OrganizationNumber>
       </ReportHeader>
  </GrobReport>

What i want is to generate a set, that contains:

OrganizationReportReferenceNumber  OrganizationNumber
=================================  ==================
1                                  4
2                                  4
3                                  4
4                                  4

i\'ve tried:

SELECT 
    foo.value(\'/ReportHeader/OrganizationReportReferenceIdentifier\') AS ReportIdentifierNumber,
    foo.value(\'/ReportHeader/OrganizationNumber\') AS OrginazationNumber
FROM CDRBatches.RawXML.query(\'/GrobReportXmlFileXmlFile/GrobReport/ReportHeader\') foo

but that doesn\'t work. i\'ve tried:

SELECT 
    foo.value(\'/ReportHeader/OrganizationReportReferenceIdentifier\') AS ReportIdentifierNumber,
    foo.value(\'/ReportHeader/OrganizationNumber\') AS OrginazationNumber
FROM RawXML.nodes(\'/GrobReportXmlFileXmlFile/GrobReport/ReportHeader\') bar(foo)

But that doesn\'t work. The XPath expression

/GrobReportXmlFileXmlFile/GrobReport/ReportHeader

is correct; in any other xml system it returns:

<ReportHeader>
    <OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
    <OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
    <OrganizationNumber>4</OrganizationNumber>
</ReportHeader>

So, it\'s obvious from my queries that i\'d like to see. After reading a dozen Stackover questions and answers, i\'m no closer to solving the problem.


回答1:


SELECT  b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    Batches b
CROSS APPLY b.RawXml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol);

Demo: SQLFiddle




回答2:


This works, been tested...

SELECT  n.c.value('OrganizationReportReferenceIdentifier[1]','varchar(128)') AS 'OrganizationReportReferenceNumber',  
        n.c.value('(OrganizationNumber)[1]','varchar(128)') AS 'OrganizationNumber'
FROM    Batches t
Cross   Apply RawXML.nodes('/GrobXmlFile/Grob/ReportHeader') n(c)  



回答3:


Try this:

SELECT RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationReportReferenceIdentifier/node())[1]','varchar(50)') AS ReportIdentifierNumber,
       RawXML.value('(/GrobXmlFile//Grob//ReportHeader//OrganizationNumber/node())[1]','int') AS OrginazationNumber
FROM Batches



回答4:


if you have only one xml in your table, you can convert it in 2 steps:

CREATE TABLE Batches( 
   BatchID int,
   RawXml xml 
)

declare @xml xml=(select top 1 RawXml from @Batches)

SELECT  --b.BatchID,
        x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
        x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM    @xml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol)


来源:https://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes

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