Of course I could name the objects in my list all manually like this:
#create dfs
df1<-data.frame(a=sample(1:50,10),b=sample(1:50,10),c=sample(1:50,10))
df2<-data.frame(a=sample(1:50,9),b=sample(1:50,9),c=sample(1:50,9))
df3<-data.frame(a=sample(1:50,8),b=sample(1:50,8),c=sample(1:50,8))
#make them a list
list.1<-list(df1=df1,df2=df2,df3=df3)
But it makes a lot of work if I have let's say 50 objects with long names. So is there any way to automate this and make the names inside the list the same as the outside objects?
Find the names, then call mget
.
If there is a pattern to the names of each individual variable, then this is straightforward.
var_names <- paste0("df", 1:3)
mget(var_names, envir = globalenv()) #or maybe envir = parent.frame()
If the naming system is more complicated, you can use regular expressions to find them, using something like
var_names <- ls(envir = globalenv(), pattern = "^df[[:digit:]]+$")
If you just want to name a list with names from the environment that share something, in this case 'df':
names(list.1) <- grep("df",ls(),value=TRUE)
If you want to push your environment into a list:
list.1 <- globalenv()
list.1 <- as.list(list.1)
To reverse the process see ?list2env
来源:https://stackoverflow.com/questions/15387727/use-object-names-as-list-names-in-r