Filter duplicate options from select dropdown

我与影子孤独终老i 提交于 2019-11-28 23:37:47

You can do it with a simple loop - there may be a cleverer way to handle this with jQuery selectors that I'm not seeing, though. The following should work:

var usedNames = {};
$("select[name='company'] > option").each(function () {
    if(usedNames[this.text]) {
        $(this).remove();
    } else {
        usedNames[this.text] = this.value;
    }
});

Edit: Here's a functional-style one-liner that does it with the help of the excellent Underscore.js, although the previous version is almost certainly more efficient:

_.each(_.uniq(_.pluck($("select[name='company'] > option").get(), 'text')), function(name) { $("select[name='company'] > option:contains(" + name + ")").not(":first").remove(); });

You can do something like this:

var previousOption;
$('select[name=company] option').each(function() {
    if (this.text == previousOption) $(this).remove();
    previousOption= this.text;
});

You can try the following code, it will remove the duplicates regardless of their position. Here #targetSelect is your target Dropdown

var a = new Array();
$(#targetSelect).children("option").each(function(x){
test = false;
b = a[x] = $(this).text();
for (i=0;i<a.length-1;i++){
if (b ==a[i]) test =true;
}
if (test) $(this).remove();
}); 
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